Explanation:
Since, NaCl exists as and in solution. Therefore, Van't Hoff factor (i) will be equal to 2.
Now, we assume that there are "n" moles of NaCl in the given solution. And, we assume that there is 1 kg of solvent (water).
So,
0.264 =
n = 0.132
Also, moles of water will be calculated as follows.
Moles of water =
= 55.56 mol
Hence, mole fraction of NaCl is calculated as follows.
Mole fraction =
=
Hence, mole fraction of NaCl will be .
At , the vapor pressure will be calculated as follows.
71.9 - p = 18.98
p = 52.92 torr
Therefore, vapor pressure of the given solution is 52.92 torr.
1.4406 × 10⁻⁶ is the Ka(dissociation constant) for the acid.
The equilibrium constant for the reaction of an acid with water is the acid dissociation constant, where the acid, HA separates into H⁺ and A⁻ ions.
The acid dissociation constant is represented by (Ka).
So let's first imagine that the given monoprotic acid is HA.
HA will dissociate into H⁺ and A⁻ ions.
HA ⇒ H⁺ and A⁻
The formula used for Ka is
Ka = [H⁺] [A⁻] / [HA]
Given
pH = 2.83
[HA] = 1.50 M
From the given pH, we can calculate [H⁺] and [A⁻]
[H⁺] = [A⁻] = 1 × = 1.47 × 10⁻³ M
Ka = 1.47 × 10⁻³ × 1.47 × 10⁻³ / 1.50
Ka = 1.4406 × 10⁻⁶
Hence, 1.4406 × 10⁻⁶ is the Ka for the acid.
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Answer: a)
b)
Explanation:
The reaction is :
Rate = Rate of disappearance of = Rate of appearance of
Rate = =
Rate of disappearance of = =
a) Rate of disappearance of =
Rate of appearance of =
b) Rate of appearance of =
Principal quantum number
magnetic quantum number
subsidiary quantum number
spin quantum number
The best method to solve how many grams of sodium nitrate that will be dissolve in water at 20 degrees Celsius is to use solubility table. Based on the solubility table, 88.3 g will dissolve in water in a 100g NaNO3. Therefore, get the percentage and multiply it to 50g. The answer is 44.15g