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labwork [276]
3 years ago
8

What the correct answer

Chemistry
1 answer:
True [87]3 years ago
3 0

Answer:

none

Explanation:

the correct option would be Ar 3d3 4s2

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How do you calculate atomic number
kifflom [539]
The number<span> of protons in the nucleus of an </span>atom is equal to <span>the </span><span>atomic number of an element. You can also find it by subtracting the number of neutrons from the atomic mass. Atomic Number = Atomic Mass - No. of Neutrons.</span>
4 0
3 years ago
Leopard seals are animals adapted to survive in the freezing conditions of Antarctica. Individual leopard seals vary in their di
andreev551 [17]

Answer:

B. Thicker layer of blubber

Explanation:

For the leopard seals to survives this harsh environment, it must have a thicker layer of blubber

Blubber is a thick layer of fat. It is called the adipose tissues and found in most marine organisms.

  • This layer helps in insulating the body against heat loss.
  • By so doing, the animal is able to conserve internal heat.
  • They have low thermal conductivity and do not easily lose heat or gain heat as such.
6 0
3 years ago
A student places one piece of chalk into a bowl with vinegar and another into a bowl with water. The next day she observes that
USPshnik [31]

Heavy rainfall causes a landslide. Hence, option A is correct.

<h3>What is a landslide?</h3>

A landslide is defined as the movement of a mass of rock, debris, or earth down a slope.

Water can trigger landslides and mudslides because it alters the pressure within the slope, which leads to slope instability.

Consequently, the heavy water-laden slope materials (soil, rock, etc.) will succumb to the forces of gravity.

Hence, option A is correct.

Learn more about the landslide here:

brainly.com/question/16151931

#SPJ1

6 0
2 years ago
What is the mass of KNO3 should be used to prepare 2.00 L of a 0.700 M solution?
Dmitry [639]

Answer:

141.4g

Explanation:

Moles= conc. ×vol

m/M = 0.7×2

m/101 = 0.7×2

m= 141.4g

3 0
3 years ago
What is the pH of a 0.222 M acetic acid solution?
Oksi-84 [34.3K]

pH=2.7

<h3>Further explanation</h3>

Acetic acid = weak acid

\tt [H^+]=\sqrt{Ka.M}

Ka = acid ionization constant

M = molarity

Ka for Acetic acid(CH₃COOH) : 1.8 x 10⁻⁵

\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.222}\\\\=0.001998=1.998\times 10^{-3}

\tt pH=3-log~1.998=2.7

7 0
3 years ago
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