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labwork [276]
3 years ago
8

What the correct answer

Chemistry
1 answer:
True [87]3 years ago
3 0

Answer:

none

Explanation:

the correct option would be Ar 3d3 4s2

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What number completes the missing part of this nuclear equation?:
hammer [34]

Answer:

hi

Explanation:

7 0
4 years ago
Read 2 more answers
If 5.57 g of Ag2O is sealed in a 75.0-mL tube filled with 760 torr of N2 gas at 28 ∘C, and the tube is heated to 310 ∘C, the Ag2
Snezhnost [94]

Answer: Total pressure = 7293.2 torr or 9.60 atm

Explanation:

<em>Total pressure = partial pressure of nitrogen + partial pressure of oxygen</em>

The partial pressure due to nitrogen is determined using the equation of Gay-Lussac's law: <em>P₁/T₁=P₂/T₂</em>

P₁ = 760 torr = 1atm, T₁ = 28∘C = (273+28)K = 301k, P₂ = ?, T₂ = 310∘C =(310+273)K = 583K

P₂ = P₁ T₂/ T₁

P₂ = 760 * 583 / 301 = 1472.03 torr

The pressure due to Oxygen gas produced is calculated thus:

Balanced equation of the decomposition of Ag₂O at s.t.p. is as follows;

2Ag₂O ----> 4Ag + O₂(g)

2 moles of Ag₂O produces 1 mole of O₂

molar mass of Ag₂O = (2*108 + 16)g = 232g/mol

molar volume of gas at s.t.p. = 22.4L

2*232g i.e. 464g of Ag₂O produces 22.4L of O₂

5.57g of Ag₂O will produce 5.57g*22.4L/464g = 0.269L or 269mL of O₂

Using the General gas equation  P₁V₁/T₁=P₂V₂/T₂

P₁ = 1atm = 760 torr, V₁ = 269mL, T₁=273K, P₂ = ?, V₂= 75mL, T₂ = 583K

P₂ = P₁V₁T₂/V₂T₁

P₂ = 760*269*583 / 75*273

P₂ = 5821.17 torr

Total pressure = (1472.03 + 5821.17) torr

Total pressure = 7293.2 torr or 9.60 atm

7 0
3 years ago
a 0.1 kg slinky sits at the top of a staircase with 14 J of potential energy. How high is the staircase?
Bezzdna [24]

Answer: The staircase is 14.28 m high.

Explanation:

Given : Mass = 0.1 kg

Potential energy = 14 J

Potential energy is the energy occupied by the position of a substance. Therefore, formula for potential energy is as follows.

P.E = mgh

where,

m = mass

g = gravitational energy = 9.8 m/s^{2}

h = height of object

Substitute the values into above formula as follows.

P.E = m \times g \times h\\14 J = 0.1 kg \times 9.8 m/s^{2} \times h\\h = \frac{14 J}{0.1 kg \times 9.8 m/s^{2}}\\= \frac{14 J}{0.98 m kg/s^{2}}\\= 14.28 Js^{2}/ mkg          (1 J s^{2}/m kg = 1 m)\\= 14.28 m

Thus, we can conclude that the staircase is 14.28 m high.

5 0
3 years ago
Number of moles in 145.7 g of squaric acid
Nesterboy [21]
To find moles : moles= Mass (C₄H₂O₄) / RFM (C₄H₂O₄)

so moles = 147.7 / 114 = <span>1.2956mol

hope that helps </span>
3 0
3 years ago
Using the equation above, how many moles of Na are produced when 2.75 moles of H2 react with excess NaCl? will give BRAINLIEST
almond37 [142]

Answer:

5.5 moles of sodium are produced

Explanation:

Given data:

Number of moles of hydrogen = 2.75 mol

Number of moles of Na produced = ?

Solution:

Chemical equation:

H₂ + 2NaCl      →       2HCl + 2Na

Now we will compare the moles of hydrogen and sodium from balance chemical equation:

                    H₂         :       Na

                     1          :       2

                   2.75      :       2/1×2.75 = 5.5 mol

Thus, 5.5 moles of sodium are produced.

5 0
3 years ago
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