The area of a circle is π (radius²)
The area of the outer (2-ft) circle is π (2²) = 4 π square feet.
The area of the inner (1-ft) circle is π (1²) = 1 π square feet.
The inner circle covers 1/4 of the area of the outer circle.
So if the ant wanders around totally aimlessly and randomly, and there's no way to
know where he came from, where he is now, or where he's going next, and there's
an equal chance of him being <em><u>anywhere in the big circle</u></em> at any time, then there's a
<u>25% chance</u> of him being inside the small circle at any time, because 1/4 of the
total area is in there.
That's choice c).
For this case we have the following equation:
P (t) = P (1 + r / n) ^ (n * t)
Where,
P: initial investment
r: interest
n: periods
t: time
she will take on her 45th birthday:
for t = 25:
P (25) = 1000 * (1 + 0.0165 / 4) ^ (4 * 25)
P (25) = 1509.31 $
Answer:
The future value of this investment when she takes her trip is:
P (25) = 1509.31 $
Step-by-step explanation:
the equations are :-
=》d = 40m + 200
=》d = 50m
here, by equalising both equations.
( since, d = d )
=》40m + 200 = 50m
=》50m - 40m = 200
=》10m = 200
=》m = 200 ÷ 10
=》m = 20
now,
=》d = 50m
=》d = 50 × 20
=》d = 1000
Answer:
The exact area is ![5\pi](https://tex.z-dn.net/?f=5%5Cpi)
Step-by-step explanation:
The area of the major circle is subtracted from the area of the minor circle (blank)
Major circle
![r=\frac{6}{2} =3](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B6%7D%7B2%7D%20%3D3)
![A=\pi r^{2} =\pi (3)^{2} =\pi (9)=9\pi](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D%20%3D%5Cpi%20%283%29%5E%7B2%7D%20%3D%5Cpi%20%289%29%3D9%5Cpi)
Minor circle:
![r=\frac{4}{2} =2](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B4%7D%7B2%7D%20%3D2)
![A=\pi r^{2} =\pi (2)^{2} =\pi (4)=4\pi](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D%20%3D%5Cpi%20%282%29%5E%7B2%7D%20%3D%5Cpi%20%284%29%3D4%5Cpi)
The shaded area:
![9\pi -4\pi =5\pi](https://tex.z-dn.net/?f=9%5Cpi%20-4%5Cpi%20%3D5%5Cpi)
Hope this helps