Peter makes a trip from Chappaqua to Southampton, a distance of 360 miles, in 5 hours. At this
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Answer:
The answer is B) 0.57.
Step-by-step explanation:
In this problem we have to apply queueing theory.
It is a single server queueing problem.
The arrival rate is and the service rate is
.
The proportion of time that the server is busy is now as the "server utilization"and can be calculated as:
where c is the number of server (in this case, one server).
The dimensions of the image are twice the dimensions of the preimage,
which indicates that the transformation is a dilation.
- The transformation <em>T</em> is; <u>a dilation transformation with a scale factor of 2, D₂</u>
Reasons:
The transformation applied to ΔABC = T
The image of ΔABC following the transformation, T = ΔA'B'C'
The perimeter of ΔA'B'C' = Twice the perimeter of ΔABC
Therefore, we have;
A'B' + B'C' + A'C' = 2 × (AB + BC + AC)
Which gives
A'B' + B'C' + A'C' = 2·AB + 2·BC + 2·AC
By similar triangles, we have the ratio of corresponding sides as follows;
Which gives;
A'B' = 2·AB
Therefore;
- Triangle ΔA'B'C' is twice the dimension of triangle ΔABC, and <em>T</em> is <u>a dilation transformation with a scale factor of 2, D₂</u>
Learn more about dilation transformation here: