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shusha [124]
3 years ago
6

Suppose a school has 20 classes: 16 with 25 students in each, three with 100 students in each, and one with 300 students for a t

otal of 1000 students. -g
Mathematics
1 answer:
expeople1 [14]3 years ago
3 0
16 classes have 25 students each which EQUALS a total of 400 students and 3 classes which each have 100 students each which EQUALS a total of 300 and 1 class has a total of 300 students and the total number of students is 1000
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95 students choose to attend one of three after school activities: footbal,l tennis or running. There are 28 boys. 38 students c
liberstina [14]

Answer:

34/95

Step-by-step explanation:

Since 38 students choose football and 23 students chose tennis, then 95 - 38 - 23 = 34 students chose running. The probability is 34 / 95.

6 0
4 years ago
Janell ran a race 11.4 seconds faster than Hilda. Hilda ran the race 7.2 seconds slower than Gracie. If the average (mean) of th
yulyashka [42]

Answer:

X= Gracie

X+7.2=Hilda

X+7.2-11.4=Janell

(X+X+X+7.2+7.2-11.4)÷3=62.6

(3x+3)÷3=62.6

3X+3=187.8 (I arrive at 187.8 because I multiple 62.6 by 3)

3X=187.8-3

3X=184.8

3X/3=184.8/3

X=61.6

Step-by-step explanation:

GRACIE X=61.6

Hilda X+7.2=61.6+7.2=68.8

Janell X+7.2-11.4=61.6+7.2-11.4= 57.4

6 0
4 years ago
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
3 years ago
R + s² at r = 4, s = 1 ( Pls show work) AND NO LINKS THX UwU
icang [17]

r+s^2

4+1^2

4+2

6

Hopefully this helped

Cani get the brainliest please

5 0
3 years ago
20 POINT QUESTION - PLEASE HELP!
mash [69]
After 100 more minutes, the rate has gone from 30 to 80, increasing by 50. 100 divided by 50 is 2 so for every 2 minutes she is charged one dollar, but per minute the rate is 50 cents per minute. Hope this helps :)
5 0
3 years ago
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