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erica [24]
2 years ago
8

Bill went on a very long run, so he ran kind of slowly. He ran 2 miles in 30 minutes. How many miles would he run in three hours

?
Mathematics
1 answer:
FromTheMoon [43]2 years ago
7 0

Answer:

12 miles

Step-by-step explanation:

There are 3 hours = 180 minutes

180÷30=6

6×2=12

Hope that helps!

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x=5

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Arlecino [84]

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Step-by-step explanation: the answer is x^2+10x+21

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For the 50 students in an art contest, there will be 1 prize for first-place, 1 prize for second-place, and 3 prizes for honorab
Sonja [21]

Step-by-step explanation:

there are 50 students and 5 prizes (1 + 1 + 3).

so, already in natural language we would say "there is 1 prize for every 10 students".

formally, remember the rule of probability : desired outcomes over total possible outcomes.

this is here

5/50 = 1/10 = 0.1

your can see it also this way :

if there was only 1 prize, each student would have a chance of 1/50 of winning.

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6 0
2 years ago
a boat travels upstream on the allegheny river for 2 hours. the return trip only takes 1.7 hours because the boat travels 2.5 mi
Gre4nikov [31]
To solve this we are going to use the speed equation: S= \frac{d}{t}
where
S is speed 
d is distance
t time 

We know from our problem that the upstream trip takes 2 hours, so t_{u}=2. We also know that the downstream trip takes 1.7 hours, so t_{d}=1.7. Notice that the distance of both trips is the same, so we are going to use d to represent that distance.
Now, lets use our equation to relate the quantities:

For the upstream trip:
S_{u}= \frac{d}{t_{u} }
S_{u}= \frac{d}{2} equation (1)

For the downstream trip:
S_{d}= \frac{d}{t_{d} }
S_{d}= \frac{d}{1.7} equation (2)

We know that the boat travels 2.5 miles per hour faster downstream, so the speed of the boat upstream will be the speed of the boat downstream minus 2.5 miles per hour:
S_{u}=S_{d}-2.5 equation (3)

Replacing (3) in (1):
S_{u}= \frac{d}{2}
S_{d}-2.5= \frac{d}{2} equation (4)

Solving for d in equation (2):
S_{d}= \frac{d}{1.7}
d=1.7S_{d} equation (5)

Replacing (5) in (4):
S_{d}-2.5= \frac{d}{2}
S_{d}-2.5= \frac{1.7S_{d}}{2}
2(S_{d}-2.5)=1.7S_{d}
2S_{d}-5=1.7S_{d}
0.3S_{d}=5
S__{d}= \frac{5}{0.3}
S_{d}= \frac{50}{3} equation (6)

Replacing (6) in (5)
d=1.7S_{d}
d=1.7( \frac{50}{3} )
d= \frac{85}{3} miles

We can conclude that the boat travel \frac{85}{3}, which is approximately 28.3 miles, in one way.

5 0
3 years ago
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