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2 years ago

8

Bill went on a very long run, so he ran kind of slowly. He ran 2 miles in 30 minutes. How many miles would he run in three hours

?

1 answer:

FromTheMoon [43]2 years ago

7 0

Answer:

12 miles

Step-by-step explanation:

There are 3 hours = 180 minutes

180÷30=6

6×2=12

Hope that helps!

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Plz help me will give brainliest

rosijanka [135]

Answer:

10

Step-by-step explanation:

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2 years ago

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Bobby put 1/3 of his lawn mowing money into his savings and uses the remaining 2/5 to buy a video game. If he has $12 left, how

Alexeev081 [22]

Given:

Bobby put 1/3 of his lawn mowing money into his savings

He uses the remaining 2/5 to buy a video game.

He has $12 left.

To find:

The amount did he have at first.

Solution:

Let x be the initial amount.

Bobby put 1/3 of his lawn mowing money into his savings. So, the remaining amount is

$x-\dfrac{1}{3}x=\dfrac{2}{3}x$

He uses the remaining 2/5 to buy a video game. Then the remaining amount is

$Remaining=\dfrac{2}{3}x-\dfrac{2}{3}x\times \dfrac{2}{5}$

$Remaining=\dfrac{2}{3}x-\dfrac{4}{15}x$

$Remaining=\dfrac{10x-4x}{15}$

$Remaining=\dfrac{6x}{15}$

$Remaining=\dfrac{2x}{5}$

It is given that the remaining amount is $12.

$12=\dfrac{2x}{5}$

$12\times 5=2x$

$60=2x$

Divide both sides by 2.

$\dfrac{60}{2}=x$

$30=x$

Therefore, Bobby have $30 at first.

6 0

2 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

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3 years ago

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murzikaleks [220]

Answer:

I think it's AB=BC.

Step-by-step explanation:

*I'm not in college, nor anywhere near college-level math, just a heads-up.*

Anyway, here's what I think. I turned my head around a bit to different angles, and I noticed the angle AB is the exact same length as BC, and both make the triangle a right angle. Try it if ya want, and see what happens. Sorry if this's wrong. I do hope it helps!

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3 years ago

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Of a number is what percentage of that number?<br>

earnstyle [38]

Answer:

13/10 = 130%

13/10 x 100

= 130%

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3 years ago