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Ratling [72]
3 years ago
15

Identify the rule for the following pattern:

Mathematics
2 answers:
vampirchik [111]3 years ago
6 0

Answer:

Step-by-step explanation:add by 13

12 + 13 = 25

25+ 13= 38

Arturiano [62]3 years ago
6 0
You add by 13 each time
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PLEASE HELP ME OUT...
katrin2010 [14]

Answer:

area = 144\pi

Step-by-step explanation:

volume =  \frac{4}{3} \pi {r}^{3}  \\  \\ 288\pi =  \frac{4}{3} \pi {r}^{3} \\  \\ 3(288\pi) = 4\pi {r}^{3} \\  \\  \frac{3(288\pi)}{4\pi}  =  {r}^{3}  \\  \\ 216 =  {r}^{3}  \\  \\ r =  \sqrt[3]{216}  \\ r = 6

area = 4\pi {r}^{2}  \\ area = 4\pi ({6}^{2})  \\ area = 144\pi

7 0
4 years ago
Pleas someone help me with this it's my last question
ruslelena [56]

Answer:

we need to find out if the following get x = 2 as a final product

-2(x-4) = 4

-2x + 8 = 4

-2x = -4

x = 2

so it is a solution

26/x = 13

26 = 13x

x = 26/13

x = 2

so it’s a solution

-3.8x = -7.4

x = 7.4/3.8 ≠ 2

you get ≈ 1.95

so it’s not a solution

4(x-1) - 3(x-2) = -8

4x - 4 - 3x + 6 = -8

x + 2 = -8

x = -10

so it’s not a solution

5 0
3 years ago
Read 2 more answers
3x - 6 + z (if x =9) (if z = 1 )​
solmaris [256]

Answer:

<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you </u></em><em><u>dear!</u></em>

8 0
3 years ago
Read 2 more answers
Ype the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
rewona [7]

Answer:

4/8 or 1/2

Step-by-step explanation:

Convert all size to x/8

1/4=2/8 and 1/2=4/8

Multiply size of beaker by how many there are filled

1/8 * 2= 2/8

2/8*7= 14/8

4/8*3 =12/8

then add all of them together = 28/8

convert 4 liters to 32/8

Subtract 32/8 - 28/8 = 4/8

4 0
3 years ago
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
3 years ago
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