All categories

4 years ago

HELP!!!! this is very confusing I understand but I can't find the mistake or the right quotient.

Mathematics

1 answer:

Scorpion4ik [409]4 years ago

3 0

Part A:
Aaron forgot to turn the second fraction <span>upside down.
</span>
Part B:
$4: \frac{1}{4}=4* \frac{4}{1}= \frac{4*4}{1}=16$

You might be interested in

Please help quick!!!

lara31 [8.8K]

Answer:

the most accurate answer would be option 3 relatively speaking

Step-by-step explanation:

6 0

3 years ago

A robot's height is 1 meter 20 centimeters. how tall is the robot in millimeters?

jeyben [28]

Answer: The height of the robot is 200 millimeters

Step-by-step explanation:

6 0

3 years ago

Which travels faster: a car that travels 130 miles in 2 hours at a constant speed or a train that travels 300 miles in 5 hours a

Vsevolod [243]

Answer:

the train travels faster than the car

Step-by-step explanation:

first solve for the train multiply 130 by 2 to have it for 4 hours and that would be the car travels 260 miles in 4 hours then divide 130 by 2 to get to five hours which will be the car travels 325 miles in 5 hours so therefore the answer would be the trains travels faster hope this helped :-)

3 0

3 years ago

Read 2 more answers

3.2x20 show work please

Alexeev081 [22]

20 x 3.2 = 64.0

It is equal to 64 because of you do long multiplication, it is 32 x 20 then add back in the decimal point in between the 4 and 0 for the answer.

6 0

4 years ago

A chemical substance has a decay rate of 6.9% per day. The rate of change of an amount N of the chemical is given by the equatio

GaryK [48]

Answer:

a) $N=N_0e^{-0.069t}$

b) $N=696.9$ grams

c) $t=10$ days

Step-by-step explanation:

We are going to use separation of variables to solve.

Get all your t's to one side and your N's to opposing side.

$\frac{dN}{dt}=-0.069N$

Multiply both sides by $dt$ :

$dN=-0.069N dt$

Divided both sides by $N$ :

$\frac{dN}{N}=-0.069 dt$

Integrate both sides:

$\ln|N|=-0.069t+C$

The equivalent exponential form is:

$e^{-0.069t+C}=N$

Using law of exponents you can write this as:

$e^{-0.069t}e^C=N$

$e^C$ is just a positive constant that I'm going to replace with K:

$e^{-0.069t}K=N$

Applying the symmetric property of equality:

$N=e^{-0.069t}K$

Applying the commutative property of multiplication:

$N=Ke^{-0.069t}$

K actually represents the initial amount of chemical substance since when plugging in 0 for t you get K for N, like so:

$N=Ke^{-0.069 \cdot 0}$

$N=Ke^{0}$

$N=K(1)$

$N=K$

We are given at time 0 the amount of chemical substance,N, is K. They want us to represent this value with $N_0$ instead. So the exponential equation is: