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3 years ago

11

HELP!!!! this is very confusing I understand but I can't find the mistake or the right quotient.

1 answer:

Scorpion4ik [409]3 years ago

3 0

Part A:
Aaron forgot to turn the second fraction <span>upside down.
</span>
Part B:
$4: \frac{1}{4}=4* \frac{4}{1}= \frac{4*4}{1}=16$

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The diagram shows a sector of a circle radius 10cm

Yuki888 [10]

Answer:

$\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}$

Step-by-step explanation:

$\text{Perimeter of the sector = Radius + arc length + radius}$

$\text{Radius = 10 cm}$

$\text{Perimeter of the sector = 10 + arc length + 10 }$

$\text{Perimeter of the sector = 20 + arc length }$

$\text{arc length = (sector angle/ 360 ) * perimeter of the circle}$

$\text{Perimeter of a circle }=2\pi r$

$\text{sector angle} = 135$

$\text{arc length} = (135/ 360 ) * 2\pi (10)$

$= (3/8) 20\pi$

$= 15\pi /2$

$\text{Using }\pi =3.14$

$= 15 * 3.14 /2$

$= 23.55$

$\text{Perimeter of the sector = 20 + 23.55}$

$= 43.55$

$= 43.6 cm$

$\text{perimeter of the sector = 43.6 cm }$

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2 years ago

3. A car starts a trip with 20 gallons of gas in its tank. The car traveled at an average

Helga [31]

Answer:

32.5%

Step-by-step explanation:

first we will have to calculate how much miles the car traveled, to do that we will multiply the speed by hour long the car was traveling for which is

65*3=195

During those 195 miles the car used 1 gallon for every 30 miles which means it used 6.5 gallons of its tank

195/30=6.5

6.5 gallons is 32.5% of 20 gallons

6.5/20=0.325

0.325 * 100 = 32.5%

3 0

3 years ago

How do you find the equation to 1/3 of 27?

NeX [460]

To find 1/3 of 27 divide 27 by the denominator (which in this case would be 3) then multiply by the numerator (which is one) so you'd do 27 divided by 3 then multiply by 1

8 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago

Sin0=12/37 find tan0

alexira [117]

Answer:

$\large{ \tt{❃ \: EXPLANATION}} :$

We're provide - Sin θ = $\frac{12}{37}$ which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = $\tt{ \frac{p}{h}}$ ] . We're asked to find out tan θ ].

$\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :$

$\large{ \tt{❊ \: {h}^{2} = {p}^{2} + {b}^{2} }}$

$\large{ \tt{⇢ {p}^{2} + {b}^{2} = {h}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = {h}^{2} - {p}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = {37}^{2} - {12}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = 1369 - 144}}$

$\large{ \tt{ ⇢{b}^{2} = 1225}}$

$\large{ \tt{⇢ \: b = \sqrt{1225}}}$

$\large{ \tt{⇢ \: b = 35 \: \text {units}}}$

Now , We know - Tan θ= $\tt{ \frac{perpendicular}{base} }$ . Just plug the values :

$\large{ \tt{➝ \: Tan \: \theta = \frac{p}{b} = \boxed{ \tt{ \frac{12}{35} }}}}$

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5 0

3 years ago