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3 years ago

14

given the probability distribution of an random variable X below,compute for the variance and standard deviation X 1 2 3 4 P(X)

1/5 1/10 2/5 3/10

1 answer:

lisabon 2012 [21]3 years ago

7 0

Answer is quantom physics cant equate to the sum of the x

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247 students went on a field trip. six buses were filled and 7 students traveled in cars. How many students were in each bus ?

Nuetrik [128]

from all the 247 students, 7 went on by cars, meaning they didn't fit in the buses, so they students that went in the buses are 247 - 7 = 240.

now, we know there were 6 buses, so dividing 240 evenly by 6, 240/6 = 40.

4 0

3 years ago

ray OJ bisects angle IOK, if angle IOJ= 2x-5 and measure of angle JOK=x+11, then find measure of angle IOJ

Mashutka [201]

2x-5=x+11
x-5=11
x=16
2(16)-5
32-5
27=IOJ

8 0

3 years ago

Read 2 more answers

Please refer to the image

Dafna11 [192]

I do not know what to answer here, you did not include the question itself.

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3 years ago

Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.

tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: $\frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3}$ square units

(22)

Similar to (21)

Area = $216\sqrt{3}$ square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

$altitude=\frac{\sqrt{3}}{2}*side$

$side = \frac{36}{\sqrt{3}}$

Hence, area of the hexagon will be: $648\sqrt{3}$ square units

(24)

Given is the inradius of an equilateral triangle.

$Inradius = \frac{\sqrt{3}}{6}*side$

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = $\frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3}$ square units

4 0

3 years ago

Solve 3x + 7 > -x - 9. Show each step of your work.

Kruka [31]

Answer:

x > -4

Step-by-step explanation:

Inequalities like these are solved the same way equations are solved, except when multiplying both sides you flip the less than/greater than sign:

3x + 7 > -x -9

3x + 7 - 7 > -x -9 -7 Subtract 7 from both sides

3x > -x -16

3x + x > -x -16 + x add x to both sides

4x > -16

$\frac{4x}{4}$ > $\frac{-16}{4}$ divide both sides by 4

x > -4

In this case the inequality sign did not have to be flipped since we never multiply both sides by a negative number.

3 0

3 years ago