Find the quotient <br> 645 divided by 100

liubo4ka [24]

Answer:

The correct option is B.

Step-by-step explanation:

The amount of money, in dollars, in a savings account after x years is given by $M(x) = 10000(1.03)^{x}$

This above equation represents that $10000 becomes M(x) after x years at a rate of interest 3% compounded in each year.

Therefore, the value in the expression 1.03 represents that there is a 3 percent increase in the savings account each year.

So, the correct option is B. (Answer)

8 0

4 years ago

Use the following expression to

IgorLugansk [536]

Answer:

part A :BODMAS ( Bracket of Division Multiplication Addition Subtraction )

part b; Bracket (2+3.2) = - 2- 3.2

= 16- 2-3.2 +30-5

ADDITION:-3.2+30 = - 33.2

16-2(-33.2)30-5

14-33.2 +30-5

14-33.2 +25

-19.2+25

-44.2

Step-by-step explanation:

THE FOLLOWING EQUATION CAN ONLY BE SOLVED USING BODMAS

3 0

3 years ago

WILL GIVE BRAINLIEST IF I CAN AND 40 PTS<br> PLEASE I NEED REAL HELP

Alinara [238K]

Answer:

Step-by-step explanation:I think it's the 2nd one

3 0

3 years ago

In March 2015, the Public Policy Institute of California (PPIC) surveyed 7525 likely voters living in California. This is the 14

lbvjy [14]

Answer:

We are confident at 99% that the difference between the two proportions is between $0.380 \leq p_{Republicans} -p_{Democrats} \leq 0.420$

Step-by-step explanation:

Part a

Data given and notation

$X_{D}=3266$ represent the number people registered as Democrats

$X_{R}=2137$ represent the number of people registered as Republicans

$n=7525$ sampleselcted

$\hat p_{D}=\frac{3266}{7525}=0.434$ represent the proportion of people registered as Democrats

$\hat p_{R}=\frac{2137}{7525}=0.284$ represent the proportion of people registered as Republicans

The standard error is given by this formula:

$SE=\sqrt{\frac{\hat p_D (1-\hat p_D)}{n_{D}}+\frac{\hat p_R (1-\hat p_R)}{n_{R}}}$

And the standard error estimated given by the problem is 0.008

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion of Democrats that approve of the way the California Legislature is handling its job

$\hat p_A =\frac{1894}{3266}=0.580$ represent the estimated proportion of Democrats that approve of the way the California Legislature is handling its job

$n_A=3266$ is the sample size for Democrats

$p_B$ represent the real population proportion of Republicans that approve of the way the California Legislature is handling its job

$\hat p_B =\frac{385}{2137}=0.180$ represent the estimated proportion of Republicans that approve of the way the California Legislature is handling its job

$n_B=2137$ is the sample for Republicans

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.