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4 years ago

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Eight students share 12 mini oatmeal muffins equally and 6 students share 15 mini apple muffins equally Carmine is in both group

s of students What is the total number of mini muffins Carmine gets? Explain your solution

1 answer:

Lana71 [14]4 years ago

4 0

Group 1:
divide number of muffins by number of students

=8 ÷ 12
=8/12
reduce by 4
=2/3 muffins each in group 1

Group 2:
=6 ÷ 15
=6/15
reduce by 3
=2/5 muffins each in group 2

Add fractions together:
= 2/3 + 2/5
need common denominator
multiply 2/3 by 5 and 2/5 by 3 for common denominator of 15

=(2/3 * 5/5) + (2/5 * 3/3)
=(2*5/3*5) + (2*3/5*3)
= 10/15 + 6/15
= 16/15
= 1 1/15 muffin

ANSWER: Carmine gets 1 1/15 muffins because she was in both groups. She received 2/3 in one group, 2/5 in another group and added together she received 1 1/15 muffins.

Hope this helps! :)

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3 years ago

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1) $\sqrt{-48}=4\sqrt{3} \ i$

2) $\sqrt{-63}=3\sqrt{7} \ i$

3) $\sqrt{-72}=6\sqrt{2} \ i$

4) $\sqrt{-24}=4\sqrt{6} \ i$

5) $\sqrt{-84}=2\sqrt{21} \ i$

6) $\sqrt{-99}=3\sqrt{11} \ i$

Step-by-step explanation:

We need to simply the following :

<u>Note: For all questions given we know that </u> $\sqrt{-1}=i$ <u> using it in all the given questions.</u>

1) $\sqrt{-48}$

Factors of 48 are: 2x2x2x2x3

$\sqrt{-48}\\=\sqrt{48}\sqrt{-1} \\=\sqrt{2\times2\times2\times2\times3}\ i\\= \sqrt{2^2\times2^2\times3}\ i\\=2\times2\sqrt{3} \ i \\=4\sqrt{3} \ i$

2) $\sqrt{-63}$

Factors of 63 are: 3x3x7

$\sqrt{-63}\\=\sqrt{63}\sqrt{-1} \\=\sqrt{3\times3\times7}\ i\\= \sqrt{3^2\times7}\ i\\=3\sqrt{7} \ i$

3) $\sqrt{-72}$

Factors of 72 are: 2x2x2x3x3

$\sqrt{-72}\\=\sqrt{72}\sqrt{-1} \\=\sqrt{2\times2\times2\times3\times3}\ i\\= \sqrt{2^2\times3^2\times2}\ i\\=2\times3\sqrt{2} \ i \\=6\sqrt{2} \ i$

4) $\sqrt{-24}$

Factors of 24 are: 2x2x2x3

$\sqrt{-24}\\=\sqrt{24}\sqrt{-1} \\=\sqrt{2\times2\times2\times3}\ i\\= \sqrt{2^2\times2\times3}\ i\\=2\sqrt{2\times3} \ i \\=2\sqrt{6} \ i$

5) $\sqrt{-84}$

Factors of 84 are: 2x2x3x7

$\sqrt{-84}\\=\sqrt{84}\sqrt{-1} \\=\sqrt{2\times2\times3\times7}\ i\\= \sqrt{2^2\times3\times7}\ i\\=2\sqrt{21} \ i$

6) $\sqrt{-99}\\$

Prime factors of 99 are: 3x3x11

$\sqrt{-99}\\=\sqrt{99}\sqrt{-1} \\=\sqrt{3\times3\times11}\ i\\= \sqrt{3^2\times11}\ i\\=3\sqrt{11} \ i \\=3\sqrt{11} \ i$

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