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lara [203]
3 years ago
5

A technician is trying to access a user's files and is unable to open any folder or file. Which of the following BEST describes

the situation?
a. The folders contain older versions of the files.
b. The files are corrupted.
c. The technician needs to change the file attributes.
d. The technician does not have permission.
Computers and Technology
1 answer:
vodomira [7]3 years ago
4 0

<em>The answer is </em><em>D. The technician does not have permission. </em>

<em> </em>

<em>Folders are locked that's why he couldn't open any folder or file. There must be a prompt telling him that he doesn't have an access or authority to open those files. This could be done via Folder sharing in the network. And a shared folder can be customized by assigning the proper and correct permission to each user.</em>

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Continuous data
Elena-2011 [213]

Answer: Could be subdivided into smaller and smaller units.

Explanation:

 The continuous data are basically measured in the small units and can be easily subdivided into smaller parts without changing their actual meaning.

The continuous data also contain numeric value and can be divided into smaller and finer meaningful parts.

The continuous data can be measured according to the precision of the system. The size and volume are the example of the continuous data.

7 0
3 years ago
Write a c++ program to print even numbers from 1 to 20​
Novay_Z [31]

Answer:

#include <bits/stdc++.h>

using namespace std;

// Function to print even numbers

void printEvenNumbers(int N)

{

cout << "Even: ";

for (int i = 1; i <= 2 * N; i++) {

// Numbers that are divisible by 2

if (i % 2 == 0)

cout << i << " ";

}

}

// Function to print odd numbers

void printOddNumbers(int N)

{

cout << "\nOdd: ";

for (int i = 1; i <= 2 * N; i++) {

// Numbers that are not divisible by 2

if (i % 2 != 0)

cout << i << " ";

}

}

// Driver code

int main()

{

int N = 20;

printEvenNumbers(N);

printOddNumbers(N);

return 0;

}

Explanation:

Note: This will find both odd and even numbers, you have to change the number above to the number of your choice

For even numbers

Even number are numbers that are divisible by 2.

To print even numbers from 1 to N, traverse each number from 1.

Check if these numbers are divisible by 2.

If true, print that number.

For odd numbers

Odd number are numbers that are not divisible by 2.

To print Odd numbers from 1 to N, traverse each number from 1.

Check if these numbers are not divisible by 2.

If true, print that number

8 0
3 years ago
Distinguish between the savings and investment options.
Tanya [424]

Answer:

Savings,                          Investments

{}Certificate of deposit    Mutual fund

{}Account                         Money Market

{}                                        Gold

Explanation:

Savings is the term used to describe the proportion of ones income not spent or kept for spending at a much later date;

Saving methods includes saving money in deposit accounts, pension savings, and cash savings as well as reducing expenditures

Savings differs from investment in the sense that investments involves more risks than savings

Mutual fund

Mutual fund is a financial resource type involving the bringing together of funds gathered from several investors for investment

Money market

The money market involves buying and selling debt investments that are short terms

Gold

Gold investment is a way of diversifying risk through futures and derivatives and futures contracts

Certificate Deposit

Certificate deposit is a fixed term deposit form of savings that provides an interest on the deposit

Account

Savings and current account are meant for saving funds

8 0
3 years ago
W t f is a ground fault circuit interrupter?
LuckyWell [14K]

lol you are awesome but to break it down for you a circuit inter-putter is is a plug in the is on the floor i have 2 of these in my home. i hope this helps you Mr. w t fer lol hahahaha XD

8 0
3 years ago
Read 2 more answers
: For each of the following words identify the bytethat is stored at lower memory address and the byte that is storedat higher m
Aloiza [94]

Answer:

In a <u>little endian computer</u> -The data's least substantial byte is put at the lower address byte. The remaining information will be put in memory in order in the next three bytes.

a)1234

4 is placed at the least significant bits,so this byte stored at lower memory address.

1 is placed at the most significant bits,so this byte stored at higher memory address.

b) ABFC

C is placed at the least significant bits,so this byte stored at lower memory address.

A is placed at the most significant bits,so this byte stored at higher memory address.

c) B100

0 is placed at the least significant bits,so this byte stored at lower memory address.

B is placed at the most significant bits,so this byte stored at higher memory address.

d) B800

0 is placed at the least significant bits,so this byte stored at lower memory address.

B is placed at the most significant bits,so this byte stored at higher memory address.

5 0
3 years ago
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