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MatroZZZ [7]
3 years ago
5

GIVING 20 POINTS AND A BRAINLIEST!!!! (Really need help please!)

Mathematics
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

Step-by-step explanation:

General form of quadratic equation:

ax^2+bx+c=0

ax^2+bx=-c

To complete the square, we will divide the coefficient of x in the general quadratic equation as written above and divide by 2

I'm the question;

x^2-20x+13=0

x^2-20x=-13

The coefficient of x =-20

Divide the coefficient by 2 and square the result afterwards

-20/2= - 10

(-10)^2= 100

Add 100 to both sides of the equation

x^2-20x+100=-13+100

x^2-20x+100=87

x^2-10x-10x+100=87

x(x-10)-10(x-10)=87

(x-10)(x-10)=87

(x-10)^2=87

Answer is 10,87

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Find the area use 3.14 for the value of pi
shutvik [7]

Answer:

78.5 inches

Step-by-step explanation:

A=(pi)r^2

divide diameter by 2 to get radius

radius = 5

3.14(5)^2 = 78.5

4 0
3 years ago
Which relation is a function?<br> Can Sb help please
nikitadnepr [17]

A relation is a function if you associate exactly one output for every input. This means that, when you choose a value for x, there must be only one correspondent value for y. This only happens in the top-right parabola.

6 0
4 years ago
HELP ASAP, PLEASE!!!!
GalinKa [24]

Using the t-distribution, as we have the standard deviation for the sample, we have that the test statistic is given by:

t = \frac{-20 - 0}{\sqrt{\frac{32.66}{7}}}

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is:

H_0: \mu = 0

At the alternative hypothesis, it is tested if there is a difference, that is:

H_1: \mu \neq 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, \mu = 0 is tested at the null hypothesis, and the sample is: 20, -40, -40, 0, 20, - 60, -40, hence:

\overline{x} = -20, s = \sqrt{32.66}, n = 7.

Hence, the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{-20 - 0}{\frac{\sqrt{32.66}}{\sqrt{7}}}

t = \frac{-20 - 0}{\sqrt{\frac{32.66}{7}}}

More can be learned about the t-distribution at brainly.com/question/16313918

5 0
3 years ago
A. the series is absolutely convergent.
Dovator [93]
\displaystyle\sum_{n=1}^\infty\left(1+\frac5n\right)^n

Notice that

\displaystyle\lim_{n\to\infty}\left(1+\frac5n\right)^n=e^5\neq0

which means the series is divergent. So if this is one of those "select all that apply" questions, then both (c) and (j) are the only choices that do.
7 0
3 years ago
The illumination at a point is inversely proportional to the square of the distance of the point from the light source and direc
Ksju [112]

Answer:

ð/[2^(1/3)] + 1 or ð/2.26

Step-by-step explanation:

Step 1: Let the illumination be denoted as C

Let the two intensities be denoted as M and N respectively

Let the distance from point P to M be x and distance from P to N be (ð-x

Step 2:

Illumination at point P from M: Cm= kM/x^2

Illumination at point P from N: Cn= kN/(ð-x)^2

The sun of the illumination: Q=Cm+Cn = (kM/x^2) + (kN/(ð-x)^2)

Differentiate Q wrt x and equate to zero, we have

(-2kM/x^3) + [2kN/(ð-x)^3] = 0

Simplifying the above equation, we have

(ð-x)^3/x^3 = -2kN/-2kM

[(ð-x)/x]^3 = N/M

[(ð-x)/x] = (N/M)^(1/3)

ð-x = x[(N/M)^(1/3)]

ð = x[((N/M)^(1/3)) + 1]

Therefore, x = ð/[((N/M)^(1/3)) + 1]

Substitute M= ð/4 and N=ð/2 into equation above, we have

x = ð/[2^(1/3)] +1 or x = ð/2.26

6 0
3 years ago
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