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Law Incorporation [45]
3 years ago
13

What is the shape of the the cross section PLEASE HELP

Mathematics
1 answer:
Masteriza [31]3 years ago
4 0

Answer: The shape of the cross section will be triangular.

Step-by-step explanation:

The cross section is the shape the shows when you cut a straight line. no matter where you cut it, you will still get a triangle.

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Pacey's computer is infected with a virus. The number of files the virus corrupts doubles every 8 minutes. The following express
mixas84 [53]
The answer for plato is C The<span> expression (1.09)x reveals the approximate rate at which the files are corrupted per minute.</span>
3 0
3 years ago
Read 2 more answers
Is the following function even, odd or neither? f(x)=x^3 +4x
erica [24]

Answer:

D, neither

Step-by-step explanation:

to determine whether a function is even, odd or neither, we need to know what it means

an even function is symmetric with respect to the y-axis

an odd function is symmetric with respect to the origin

to solve an equation to see if its even or odd, we would need to substitute <em>x</em> in the equation for <em>-x</em>.

in an even function when we substitute f(-x), it should be equal to to f(x)

in an odd function when we substitute f(-x), it should be equal to -f(x)

so lets test the function given to see if its even

f(x) = x³ + 4x

f(-x) = (-x)³ + 4(-x)

f(-x) = x³ - 4x

f(-x) = x³ - 4x ≠ f(x) = x³ + 4x

comparing this to the orignal function, we see that f(-x) = x³ - 4x is not even as we did not get the same output as the original function

now we should test to see if its odd. we have already seen what f(-x) is, now lets try -f(x) and compare it to f(-x) and f(x)

-f(x) = -(x³ + 4x) -->

-f(x) = -x³ - 4x ≠ f(-x) = x³ - 4x

f(-x) = x³ - 4x ≠ f(x) = x³ + 4x

comparing this to f(x) and f(-x), we see that it not odd as we did not get the same output

so the answer is D, neither even nor odd

6 0
4 years ago
(Due in 20 minutes!)
klasskru [66]

Answer:

1.5

18 and 33

Step-by-step explanation:2.

c

5 0
2 years ago
One urn contains one blue ball (labeled b1) and three red balls (labeled r1, r2, and r3). a second urn contains two red balls (r
Flura [38]

Answer:

12 possibilities

Step-by-step explanation:

In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.

The same thing occurs in the second urn, as all balls have different labels.

The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).

For the first urn, we have a combination of 4 choose 2:

C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities

For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.

In total we have 6 + 6 = 12 possibilities.

3 0
3 years ago
Read 2 more answers
a bag contains 20 pink marbles and 12 yellow marbles. you choose a marble at random. what is the probability of selecting a pink
Sati [7]
So the total amount of marbles is: 20+12=32
there are 20 pink marbles
20/32 = 10/16 = 5/8 (simplified)
4 0
3 years ago
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