<span>The correct answer is option B. i.e. Both equation 1 and 2 have the same number of solutions. The equation 1 is |5x+6| = 41 By removing the modulus sign we get, 5x + 6 = 41 and 5x +6 = -41. Solving, 5x = 6 = 41 we get, 5x = 35 or x = 7. And, on solving 5x +6 = -41 we get, 5x = -47 or x = 9.4 Now. the second equation is |2x+13| = 28 By removing the modulus sign we get, 2x+ 13 = 28 and 2x +13 = -28. Solving, 2x = 28 -13 = 15 or x = 7.5 . And, on solving 2x +13 = -28 we get, 2x = -41 or x = -20.5.TH </span>
Answer:
A, C, E are your answers
Step-by-step explanation:
SA = LH + LW + WH + 2(1/2LH)
SA = 4*2 + 5*2 + 3*2 + 2*1/2*4*3
SA = 8 + 10 + 6 + 12
SA = 36
Answer:10
Step-by-step explanation:
