Answer:they are all straight across so drag each line to the one that is across from the equation
Step-by-step explanation:
Answer:
The slope is 2/3 and the function is y=2/3x which is a direct variation function.
Step-by-step explanation:
To find the slope of a line between two points, we use the equation
m = (y2-y1)/ (x2-x1)
where (x1,y1) and (x2,y2) are the two points
m= (4-2)/(6-3)
= 2/3
The slope of the line is 2/3
The equation of the line is
y-y1 = m(x-x1)
y-2 = 2/3(x-3)
Distribute
y-2 = 2/3x -2
Add 2 to each side
y-2+2 = 2/3x -2+2
y = 2/3x
This is a direct variation function
Let x = -6
y = 2/3(-6)
y = -4
(-6,-4)
Answer:
<em>x = 9</em>
<em>y = 36</em>
Step-by-step explanation:
<u>Lines and Angles</u>
Triangle CDE is isosceles. This means the two angles of the base DE are congruent (have the same measure):
7x + 1 = 4x + 28
Subtracting 4x + 1:
3x = 27
Dividing by 3:
x = 9
Substituting in the expression for the angles:
7x + 1 = 7*9 + 1 = 64°
The angles are 64° and 64°. The other internal angle at vertex C is 180°-64°-64°=52°. This angle is congruent with its vertical angle in the triangle ABC. We are given another angle of 43°. Thus the measure of angle A is 180°-52°-43°=85°
This last angle is equal to the expression of y:
-2(3 - y) + 19 = 85
Subtracting 19:
-2(3 - y) = 66
Removing the parentheses:
-6 + 2y = 66
Adding 6:
2y = 72
Dividing by 2:
y = 36
Final answer:
x = 9
y = 36
Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.