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nikklg [1K]
3 years ago
9

Which of the following functions would not graph as a straight line?

Mathematics
2 answers:
spin [16.1K]3 years ago
5 0

Answer:

A) f (x) = -x^{2}- 3

Step-by-step explanation:

Furkat [3]3 years ago
5 0
The answer is A. f(x)=-x^2-3
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Which properties justify the steps taken to solve the system?
Nutka1998 [239]

Answer:

X=-1

Y=1

Step-by-step explanation:

6x-12y

-18

) 6x + 4y

-

-2

Subtract the two equations

6x - 12y - (6x + 4y) = -18 - (-2)

Determine the sign

6x- 12y - 6x- 4y

=-18 + 2

Simplify

-12y

- Ay

=-18 + 2

Solve the equation

Substitute

6×+4

-2

Solve the equation

X=

6 0
2 years ago
Jane needs to solve for the value of n in the equation 10 n = 150. Which of these steps would BEST help Jane solve the equation?
Hoochie [10]

Answer:

n = 15

Step-by-step explanation:

10 x 15 = 150.

<em>Hope this helps!</em>

8 0
2 years ago
Graph the image of the figure using the transformation given.<br>reflection across y=-1​
Vikki [24]

Answer:

I'm not graphing, but I can describe the reflection as R', S', T', U':

R' = (-3, 1)

S' = (-2, 0)

T' = (-1, 2)

U' = (-2, 2)

Step-by-step explanation:

y = -1 is the line one unit below the x axis (the x axis is y=0).

To reflect any point across y=-1, we just need to leave the x coordinate as was, but the (new y) will be -2-(old y)

R = (-3, -3), R' = (-3, -2+3) = (-3, 1)

S = (-2, -2), S' = (-2, -2+2) = (-2, 0)

T = (-1, -4), T' = (-1, -2+4) = (-1, 2)

U = (-2, -4), U' = (-2, -2+4) = (-2, 2)

6 0
2 years ago
Find the valuecof x in each figure​
Jlenok [28]

X = 140

You do 110 + 30 and that gives you 140. Hope it helped!
7 0
3 years ago
The spring has a stiffness k=200n/m and is unstretched when the 25 kg block is at
g100num [7]
To solve this we are going to use the formula fro the force applied to a spring: F=ks
where
k is the spring constant 
s is the extension 

Since we know the F=ma, we can replace that in our formula and solve for a :
ma=ks
a= \frac{ks}{m}
where
a is the acceleration 
k is the spring constant
s is the extension 
m is the mass

We know for our problem that k=200, s=0.4, and m=25. So lets replace those values in our formula to find a:
a= \frac{ks}{m}
a= \frac{(200)(0.4)}{25}
a=3.5 \frac{m}{s^2}

We can conclude that the acceleration of the block when s=0.4m is 3.5 \frac{m}{s^2}.
7 0
3 years ago
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