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Mazyrski [523]
2 years ago
13

A triangle is formed with side lengths of 24 centimeters, 26 centimeters, and 10 centimeters. Is the triangle a right triangle?

A) The triangle is a right triangle because 24^2+10^2=26^2. B) The triangle is a right triangle because 2(24)+2(26)=2(10) C) The triangle is not a right triangle because 10^2+26^2=24^2. D) The triangle is not a right triangle because 24^2-26^2=10^2

Mathematics
1 answer:
storchak [24]2 years ago
8 0

Answer:

A)

Step-by-step explanation:

676=676

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Step-by-step explanation:

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2 years ago
For which value of X is the row in the table of values incorrect? The function is the quadratic function Y=3/4x^2
svet-max [94.6K]

Answer:

The row with x = 2 and y = 4 is incorrect. The y value should be y = 3 when x = 2.

==============================================================

Explanation:

Fractions can be a bit of a pain, so I'm going to be converting to decimal form to help with the computation; however, I will convert the y value results to mix number form so that it matches what the table shows.

Keep in mind that 3/4 = 0.75 when you use a calculator or long division. So a number like 2.75 means 2 & 3/4 (two and three quarters)

---------------

Let's check the first row. Plug in x = 0 and it leads to...

y = (3/4)*x^2

y = (3/4)*0^2

y = (3/4)*0

y = 0.75*0

y = 0

This shows us that row 1 is correct. When x = 0, y = 0 leading to (x,y) = (0,0).

-------------

Repeat the same basic outline of steps, but now use x = 2

y = (3/4)*x^2

y = (3/4)*2^2

y = (3/4)*4

y = 0.75*4

y = 3

So instead of 4, the proper y value is y = 3 when x = 2. This means row 2 is the answer (the row that has the incorrect values).

-------------

For the sake of completeness, let's see if the third row is correct or not. Plug in x = 3

y = (3/4)*x^2

y = (3/4)*3^2

y = (3/4)*9

y = 0.75*9

y = 6.75

y = 6 & 3/4

We see that x = 3 points to y = 6 & 3/4, so we have the correct values in this row. We can cross this off the list of choices.

-------------

Finally, let's check x = 5

y = (3/4)*x^2

y = (3/4)*5^2

y = (3/4)*25

y = 0.75*25

y = 18.75

y = 18 & 3/4

We get the proper y value. So we can also cross this off the list.


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I really need one too. Thanks for the question.
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Minimize Q=3x2+3y2​, where x+y=6.
weeeeeb [17]

Answer:

+(x + y) {}^{2}  = 6 {}^{2} \\ x {}^{2} + 2xy + y {?}^{2}  = 36

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q = 3(x {}^{2}  + y {}^{2} )

q = 3(36 - 2xy) = 108 - 6xy

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