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ivolga24 [154]
3 years ago
7

The quantity of Sensitech laser gaming mice demanded each month is related to the unit price by the equation p = 480.03x2 + 1 (0

≤ x ≤ 20) where p is measured in thousands of dollars and x in units of a thousand.(a) Find the revenue function R.(b) Find the marginal revenue function R'.(c) Compute R'(2).
Mathematics
1 answer:
stich3 [128]3 years ago
5 0

Answer:  a) p=480.03x^2+1, b) R'(x)=1440.09x^2+1 c) $5761.36.

Step-by-step explanation:

Since we have given that

Unit price is expressed as

p=480.03x^2+1

Let x be the number of units of a thousands.

So, Revenue function is given by

R(x)=px\\\\R(x)=x(480.03x^2+1)\\\\R(x)=480.03x^3+x

.(b) Find the marginal revenue function R'..

Marginal revenue function becomes,

R'(x)=3\times 480.03x^2+1\\\\R'(x)=1440.09x^2+1

(c) Compute R'(2).

R'(2)=1440.09(2)^2+1\\\\R'(2)=5760.36+1\\\\R'(2)=5761.36

Hence, a) p=480.03x^2+1, b) R'(x)=1440.09x^2+1 c) $5761.36.

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Sladkaya [172]

Answer:

Initial value is 4,000

Growth is -480

Step-by-step explanation:

Initial value is the value that you started with: hence 4000.

Growth would be how much it grows, it grows downward because it is 12% down. Next you need to find what 13% of 4000 is 100%-13%=88% .88*4000=480 or 13% of 4000.

Hope this helps

7 0
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What is the horizontal asymptote of f(x)=-2x/x+1<br> A.-2<br> B.-1<br> C.0<br> D.1
Mrrafil [7]
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7 0
3 years ago
Read 2 more answers
a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0
3 years ago
A submarine traveling 200 meters below the surface of the ocean increases its depth by 45 meters. Adam says that the new locatio
My name is Ann [436]

Answer:

The error that Adam could have made is added 45 to the depth of

submarine instead of adding -45

Step-by-step explanation:

* Lets explain how to solve the problem

- A submarine traveling 200 meters below the surface of the ocean

- Increases its depth by 45 meters

- Adam says that the new location of the submarine is -155 meters

- We need to know the error of Adam

∵ We consider the surface of the ocean is the zero level

∵ The submarine is 200 meters below the surface of the ocean

∵ Below means negative

∴ The depth of submarine is -200 meters

∵ It increases the depth by 45 meters

- <em>That means it travels down another 45 meters</em>

∵ Down means negative

∴ The depth of submarine = -200 + (-45) = -245 meters

∴ The depth of submarine is 245 below the surface of the ocean

- Adam could thought that the submarine traveled up for 45 meters

 then he add 45 to -200

∵ -200 + 45 = -155 meters

∴ The error that Adam could have made is added 45 to the

   depth of submarine instead of adding -45

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scZoUnD [109]

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