Question

Find the perimeter of the following shape, round to the nearest tenth

Answer 1

Answer:

The perimeter of the figure is:

                       17.9 units

Step-by-step explanation:

We know that the perimeter of the figure is the sum of all the side lengths of a figure i.e. it is the sum of the distance around a figure.

In the given figure the perimeter of the figure is:

Length AB+Length BC+Length CD+Length AD

Now from the figure we see that:

A is located at  (-3,5)

B is at (1,7)

C is located at (3,3)

and D at (-1,1)

Hence, by using distance formula we get:

$AB=\sqrt{(1-(-3))^2+(7-5)^2}\\\\\\AB=\sqrt{4^2+2^2}\\\\\\AB=\sqrt{20}\ units$

$BC=\sqrt{(3-1)^2+(3-7)^2}\\\\\\BC=\sqrt{2^2+4^2}\\\\\\BC=\sqrt{20}\ units$

$CD=\sqrt{(-1-3)^2+(1-3)^2}\\\\\\CD=\sqrt{4^2+2^2}\\\\\\CD=\sqrt{20}\ units$

and

$AD=\sqrt{(-1-(-3))^2+(1-5)^2}\\\\\\AD=\sqrt{20}\ units$

Hence, we get perimeter of figure is:

$=\sqrt{20}+\sqrt{20}+\sqrt{20}+\sqrt{20}\\\\=4\times \sqrt{20}\\\\\\=8\sqrt{5}\\\\\\=17.88854\ units$

Hence, to the nearest tenth we have:

      Perimeter=17.9 units

Answer 2

Answer: you take the slope of the lines rise over run and add together

Step-by-step explanation: