Answer:
666 divided by 6 is 111. So, they would need 111 vans.
Answer: The total length in kilometers is 38 km
Step-by-step explanation:
17 + 2 = 19 km is 1/2 of the total length, that is,
19 = (1/2)h
(1/2)h = 19 multiply both sides by 2
h = 2*19
h = 38 km
First definition matches with expression, second matches with equation ,third matches with algorithm and fourth matches with equation.
Given four definitions of equation, expression, algorithm but mixed.
We have to match the definitions with appropriate term.
We know that expression is a combination of numbers, symbols, fraction, coefficients, indeterminants mostly not found in equal to form. It exhibits a behaviour only.
Algorithm is a computer programming to do a specific task in a predetermined way.
Equation is a relationship between two variables expressed in equal to form. In this we have to put the value of variables and the equation gives us a value.
Hence First definition matches with expression, second matches with equation ,third matches with algorithm and fourth matches with equation.
Learn more about algorithm at brainly.com/question/13800096
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its not worth 25 points but ok here u go let's solve your equation step-by-step.
3y−1=13−4y
Step 1: Simplify both sides of the equation.
3y−1=13−4y
3y+−1=13+−4y
3y−1=−4y+13
Step 2: Add 4y to both sides.
3y−1+4y=−4y+13+4y
7y−1=13
Step 3: Add 1 to both sides.
7y−1+1=13+1
7y=14
Step 4: Divide both sides by 7.
7y
7
=
14
7
y=2
Answer:
y=2 so there your answer is this equation has one solution your welcome
You need the compound interest formula solved for time:
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (9,000 / 5,960.32) / 2 * log (1 + .042/2)
Years = log (
<span>
<span>
<span>
1.509986041</span></span></span>) / 2 * log (1.021)
Years = 0.1789729325 / 2 * 0.0090257420869
Years =
<span>
<span>
</span></span><span><span><span>0.1789729325 / 0.0180514842
</span>
</span>
</span>
<span><span><span>Years =
9.9145826746
</span>
</span>
</span>
the answer is "d"
Source:
http://www.1728.org/compint.htm