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Paha777 [63]
3 years ago
8

How do you do the math of 9.53 divided by 18

Mathematics
1 answer:
AfilCa [17]3 years ago
4 0
0.52944444444 you can simplify the decimal and you will have the answer

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(Easy) What changes about a figure after translation in terms of 2D shapes?
Lapatulllka [165]
It really does not change a whole lot, all your doing is moving it, your not adding size or subtracting size or rotating it. Just make all the points of the shape stay the same distance.

I hope this helps.
3 0
3 years ago
Plz help me quick!!!!!!!!!!!!!!!!!!!!!!!!
beks73 [17]

Answer:

Exact Form: 5/2

Decimal Form: 2.5

Mixed Number Form: 2 1/2

Step-by-step explanation:

5 0
3 years ago
Use the graph of f '(x) below to find the x values of the relative maximum on the graph of f(x):
Lana71 [14]

Answer:

You have relative maximum at x=1.

Step-by-step explanation:

-Note that f' is continuous and smooth everywhere. f therefore exists everywhere on the domain provided in the graph.

f' is greater than 0 when the curve is above the x-axis.

f' greater than 0 means that f is increasing there.

f' is less than 0 when the curve is below the x-axis.

f' is less than 0 means that f is decreasing there.

Since we are looking for relative maximum(s), we are looking for when the graph of f switches from increasing to decreasing. That forms something that looks like this '∩' sort of.

This means we are looking for when f' switches from positive to negative. At that switch point is where we have the relative maximum occurring at.

Looking at the graph the switch points are at x=0, x=1, and x=2.

At x=0, we have f' is less than 0 before x=0 and that f' is greater than 0 after x=0.  That means f is decreasing to increasing here. There would be a relative minimum at x=0.

At x=1, we have f' is greater than 0 before x=1 and that f' is less than 0 after x=1. That means f is increasing to decreasing here. There would be a relative maximum at x=1.

At x=2, we have f' is less than 0 before x=2 and that f' is greater than 0 after x=2. That means f is decreasing to increasing here. There would be a relative minimum at x=2.

Conclusion:

* Relative minimums at x=0 and x=2

* Relative maximums at x=1

3 0
2 years ago
Let f(x)=cos(x)x^-2<br> F’(x)=
kondaur [170]

f(x)=cos(x)x^{-2}\implies f(x)=\cfrac{cos(x)}{x^2}\implies \cfrac{df}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{-sin(x)\cdot x^2-cos(x)\cdot 2x}{(x^2)^2}} \\\\\\ \cfrac{df}{dx}=\cfrac{-x[x\cdot sin(x)+2cos(x)]}{x^4}\implies \cfrac{df}{dx}=\cfrac{-[xsin(x)+2cos(x)]}{x^3}

8 0
2 years ago
If rybirens (which each have 9 flowers) and figilbuttons (which each have 7 flowers). he says to his friend, i count 87 plants a
RideAnS [48]
You can subtract 9 from the 713 value and trace until you get a multiple of 7 or vice versa.

It could be one of :
 
80 figilbuttons and 7 rybirens

or

14 rybirens and 73 figilbuttons
5 0
3 years ago
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