Answer: D) csc (2π/3)
<u>Step-by-step explanation:</u>
2π/3 is in Quadrant II
Quadrant II has a negative x-value and a positive y-value.
x-values are: cos & sec
y-values are: sin & csc
tan = y/x so will be negative in Quadrant II
A) sec = -
B) tan = -
C) cos = -
D) csc = + this works!
Let us take the second equation first
2a + 2b = 6
Dividing both sides by 2 we get
a + b = 3
a = 3 - b
Putting the value of a in the first equation we get
3a + 4b = 9
3(3 - b) + 4b = 9
9 - 3b + 4b = 9
b = 9 - 9
= 0
Now putting the value of b in the second equation we get
a + b = 3
a + 0 = 3
a = 3
So the value of the unknown variable a is 3 and the value of the unknown variable b is 0.
Answer: 7
Step-by-step explanation:
Answer:
V = 64 r^(9) * s^(6)
Step-by-step explanation:
The volume of a cube is given by
V = s^3 where s is the side length
V = ( 4r^3s^2) ^3
We know that ( ab) ^c = a^c * b^c
V = 4^3 * r^3^3 * s^2^3
V = 64 * r^3^3 * s^2^3
We know that a^b^c = a^(b*c)
V = 64 r^(3*3) * s^(2*3)
V = 64 r^(9) * s^(6)
