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elena-14-01-66 [18.8K]

3 years ago

7

Container consists of two red flags, three blue flags, and three green flags. If Ron chooses two flags to keep, what is the prob

ability of choosing a red flag and then a green

1 answer:

miv72 [106K]3 years ago

7 0

2/8 because you add all th flags toether and there are only 2 red flags

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Whats 2+2 as a fraction

notka56 [123]

2 + 2 = 4

4 / 1 = 4

so the fraction form of " 2+2 (or 4) " would be " 4/1 "

8 0

3 years ago

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Va rog e urgent am nevoie de raspuns

Lady_Fox [76]

Answer: 4

<u>Explanation:</u>

f(x) = 2x - 1

f(√2) = 2√2 - 1

f(1) = 2(1) - 1

= 2 - 1

= 1

f(√3) = 2√3 - 1

*******************************************************

$\frac{f(\sqrt{2})-f(1)}{\sqrt{2}-1} +\frac{f(\sqrt{3})-f(\sqrt{2})}{\sqrt{3}-\sqrt{2}}$

= $\frac{(2\sqrt{2}-1)-1}{\sqrt{2}-1} +\frac{(2\sqrt{3}-1)-(2\sqrt{2}-1)}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1} +\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1}(\frac{\sqrt{2}+1}{\sqrt{2}+1})+\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}(\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}})$

= $\frac{4+2\sqrt{2}-2\sqrt{2}-2}{2 - 1} + \frac{6 +2\sqrt{6}-2\sqrt{6}-4}{3-2}$

= $\frac{2}{1} +\frac{2}{1}$

= 4

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3 years ago

If in quadrilateral ABCD, AB = DC and BC = DA, then diagonals AC and BD Select one:

Varvara68 [4.7K]

Answer:

<em>It's </em><em>B</em><em>, the diagonals bisect each other</em>

Step-by-step explanation:

If they were equal, it would have to be a rectangle. If they were perpendicular, it would have to be a sqaure.

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3 years ago

I will mark brainliest for correct answer

statuscvo [17]

24, it’s the lcf and is the closest number that they have in common

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3 years ago

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Brainliest to right answer hurryyyy!!!!

Lina20 [59]

The answer is 6, I hope it helps!!

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3 years ago