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ipn [44]
3 years ago
12

Elena has bought 320 tropical fish for a museum display. She bought 7 times as many triggerfish as parrotfish. How many of each

type of fish did she buy?
Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0
The total number of fish bought was 320. And you know she bought two types of fish. The best way to solve this is guess and check. It would be the fastest. So she bought 7 times as many trigger-fish as parrot fish that means the number of trigger-fish bought was 7p. This means 320 = 7p +p. So all you do is take educated guesses for the number of parrot fish and check if it is right. So if she bought 50 parrot fish. 7(50) + 50 = 400. Close but a bit high. Lets keep guessing. 7(35) + 35 = 245. So now we know the answer is between 50 and 35. So lets try 40. 7(40) + 40 =320. That works so we know she bought 40 parrot fish and 280 trigger-fish.
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The answers
bazaltina [42]

Answer:

C

Step-by-step explanation:

First cuz the y-intercept is 3 so not B or D

And the slope is -2/3

so the answer is C.

i'm not really sure about the slope part.

3 0
3 years ago
Read 2 more answers
Lf f(x) = 5x, what is f^-1(x)?
Nonamiya [84]

Answer: f^{-1}(x)=\frac{x}{5}

Step-by-step explanation:

By definition the domain of an inverse function f^-1(x) is the range of f(x) and the range of the inverse function is equal to the domain of the principal function f(x).

If you have a function f(x)=5x, then to find the inverse function, follow these steps:

1. Make y=f(x)

 f(x)=y=5x

 y=5x

2. Solve for the variable "x":

x=\frac{y}{5}

3. Exchange the variable "x" with the variable "y":

y=\frac{x}{5}

4. Exchange "y" withf^{-1}(x). Then the inverse function is:

f^{-1}(x)=\frac{x}{5}

7 0
3 years ago
1. Flight 202's arrival time is normally distributed with a mean arrival time of 4:30
Bezzdna [24]

Answer:

Step-by-step explanation:

1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min

By comparing P(0 ≤ Z ≤ 30)

P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)

Using Table

P(0 ≤ Z ≤ 1) = 0.3413

P(Z > 1) = (0.5 - 0.3413) = 0.1537

∴ P(Z > 45) = 0.1537

2)  By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)

P(Z ≤ 15 - 30/15) = P(Z ≤ -1)

Using Table

P(-1 ≤ Z ≤ 0) = 0.3413

P(Z < 1) = (0.5 - 0.3413) = 0.1587

∴ P(Z < 15) = 0.1587

3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)

P(Z ≤ 60 - 30/15) = P(Z ≤ 2)

Using Table

P(0 ≤ Z ≤ 1) = 0.4772

P(Z > 1) = (0.5 - 0.4772) = 0.0228

∴ P(Z > 60) = 0.0228

6 0
3 years ago
It costs luis 5$ to park his car at a parking meter for 2 hours. What is the price to park for 1 hour? Draw a bar model or write
Aliun [14]

Answer:

$2.50

Step-by-step explanation:

If it costs $5 for two hours and one hour is half of two hours, you take half of $5 and use it as your answer, so your answer is $2.50

3 0
3 years ago
A 2-column table with 7 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3. The sec
DochEvi [55]

The statements that are true about the intervals of the continuous function are Options 2, 4  and 5

  • f(x) ≤ 0 over the interval [0, 2].
  • f(x) > 0 over the interval (–2, 0).
  • f(x) ≥ 0 over the interval [2, ).

<h3>What is the statement about?</h3>

Looking at the values given, the intervals which satisfies the condition are known to be:

f(x)<=0 over the interval [0,2]

f(x)>0 over the interval (-2,0)

f(x)>=0 over the interval [2,∞)

Because:

Since the table with x  and f(x) values, we have to examine analyze the table and see the each option that is in line with f(x) or not .

Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)

Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]

When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)

When you look at the interval (-2,0) , the f(x)  is positive and as such, f(x)>0 over the interval (-2,0)

Looking at the interval  [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)

Therefore, Option 2, 4 and 5 are correct.

Learn more about interval from

brainly.com/question/14454639

#SPJ1

6 0
2 years ago
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