x-2 is a factor so x = 2 is a root of f(x)
This is because f(x) = (x-2)*g(x) for some polynomial g(x). We don't have to worry about what g(x) is equal to as it doesn't affect the status of the root we're after.
So,
f(x) = 0
(x-2)*g(x) = 0
x-2 = 0 or g(x) = 0
x = 2 or g(x) = 0
This shows how the factor x-2 leads to the root x = 2
Therefore, f(2) = 0
Answer: Choice D
Answer:
Side of 22 and height of 11
Step-by-step explanation:
Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:


As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank
Base area with open top 
Side area 4sh
Total surface area 
We can substitute 


To find the minimum of this function, we can take the first derivative, and set it to 0



![s = \sqrt[3]{10648} = 22](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%5B3%5D%7B10648%7D%20%3D%2022)

The answer is 89078.88 ft
1 mile = 5280 feet
Multiply 16.871 by the length value of 5280
16.871 * 5280 = 89078.88 ft
Attached is a screenshot of spreadsheet used to do this problem.
You will see the excel functions used for each column. The average score is highlighted in blue.
Answer:
The horsepower required is 235440 watt.
Step-by-step explanation:
To find : What horsepower is required to lift an 8,000 pound aircraft six feet in two minutes?
Solution :
The horsepower formula is given by,

Where, W is the horsepower
m is the mass m=8000 pound
g is the gravitational constant g=9.81
t is the time t= 2 minutes
h is the height h=6 feet
Substitute all values in the formula,



Therefore, The horsepower required is 235440 watt.