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TEA [102]
3 years ago
13

Jimmy collects nickels and dimes. Right now, he has a total of 40 coins in his piggy bank. If there are seven times as many dime

s as there are nickels, how many nickels does Jimmy have?
Mathematics
1 answer:
Colt1911 [192]3 years ago
4 0
Number of nickels plus number of dimes equals total number of coins
so
n + d = 40

then they tell us that "there are seven times as many dimes as there are nickels"
this translates to
d = 7n

we then plug that into our first equation
and get
n + 7n = 40

then we solve for n
add like terms
8n = 40

then divide both sides by 8
n = 40/8 = 5

therefore Jimmy has 5 nickels
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Read 2 more answers
Find the 80th term of the following arithmetic sequence.<br> 17, 26, 35, 44,
ASHA 777 [7]

Answer:

728

Step-by-step explanation:

formula is

Tn= a+(n-1)d

where a is the first term, d is the common difference and n is the term you are looking for

<h3>T80 = 17+(80-1)*9</h3><h3>T80= 17+ (79)*9</h3><h3>T80= 17 + 711</h3><h3>T80= 728</h3>

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3 years ago
Label the numbers that would go in each box so that each equation is true. Each equation has at least one negative number.
yKpoI14uk [10]

Answer:

1.

{2}^{2}  \times  {2}^{- 2}  =  {2}^{}

2.

\frac{2 ^{3}}{2^{2} }  =  {2}^{1}

{2}^{ - 3}  \times  {5}^{ - 3}  =  {10}^{ - 6}

hope that will help you to understand

4 0
2 years ago
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