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Please *atleast* answer one of them!

Julli [10]

Answer and Step-by-step explanation:

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1. Let's write out the equation to subtract.

7t - 2u - 3v - (t - 3v)

Distribute the negative to the t and -3v.

7t - 2u - 3v - t + 3v (The negatives cancel out)

Now simplify by combining like terms.

6t - 2u

This is the answer because the 3v and -3v cancel out.

2. I don't really understand what this is saying. Is there answer choices for this? But what I think its saying is that the lift has a constant of 2.

3. To find out the amount of terms, we would simplify the equation.

2x + 3y - 5x + yz - x

-4x + 3y + yx

Here, we can see that we have 3 terms in this expression.

-4x is the first term, +3y is the second term, and +yx is the third term.

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#teamtrees #WAP (Water And Plant)

8 0

2 years ago

Jose brought 9 pounds of rice for $4. How many pounds of rice did he get per dollar?

NikAS [45]

Answer:

1.5 pound ever dollar

Step-by-step explanation:

just calculate

7 0

2 years ago

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Rabies is a viral disease of mammals transmitted through the bite of a rabid animal. The virus infects the central nervous syste

lisabon 2012 [21]

Answer:

(a) The value of x is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.

Step-by-step explanation:

Denote the events as follows:

R = reported case of rabies is a raccoon

F = reported case of rabies is a fox

B = reported case of rabies is a bat

O = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = x.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, $\sum P(X)=1$

Compute the value of x as follows:

$\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30$

Thus, the value of x is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

$P(A^{c})=1-P(A)$

Compute the probability that a reported case of rabies is not a raccoon as follows:

$P(R^{c})=1-P(R)\\=1-0.55\\=0.45$

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

$P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15$

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

4 0

2 years ago

Consider rolling two fair dice one 3-sided the other 5-sided

Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

$1\leq x\leq 3,\quad 1\leq y \leq 5$

We have $P(X=x)=\frac{1}{3}$ and $P(Y=y)=\frac{1}{5}$ , because the dice are fair.

Now we use the assumption of independence to claim that

$P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}$

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

2 in a unique way (1+1)
3 in two possible ways (1+2, 2+1)
4 in three possible ways
5 in three possible ways
6 in three possible ways
7 in two possible ways
8 in a unique way

This implies that the probabilities of the outcomes of $W=X+Y$ are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

8 0

2 years ago

I need help can tell me tell me on a playground what is something that is shorter than a meter

Novosadov [1.4K]

One meter is 3.28 feet, so anything shorter than that. A basketball, maybe a very young child?

8 0

2 years ago

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