Answer:
they have different answers
Step-by-step explanation:
X - 13 = 4 and 13 - X = 4
for x- 13 = 4
x=4+13=17
x=17
for 13 - x = 4
13-4-x=0
9-x=0
9=x
x=9
A) (3x+30)+(x-5)+35=180
4x+60=180
4x=120
x=30
b) A=x-5
A=25
B=3x+30
B=120
Answer:
Answers are below!
Step-by-step explanation:
(2 + g) (8)
= (2 + g) (8)
Add a 8 after the 2, and flip.
= (2)(8) + (g)(8)
= 16 + 8g
= 8g + 16
= (4) (8 + -5g)
Add another 4, then flip.
= (4) (8) + (4) (-5g)
= 32 − 20g
= - 20g + 32
−7 (5-n)
= (−7) (5 + -n)
Add another 7, then flip.
= (−7) (5) + (-7) (-n)
= −35 + 7n
= 7n - 35
Use the distributive property.
a (b + c) = ab + ac
a = 8
b = 2m
c = 1
= 8 × 2m + 8 × 1
Simplify, you get 16m + 8.
Use the distributive property.
a (b + c) = ab + ac
a = 6x
b = y
c = z
= 6xy - 6xz is the answer.
Apply minus plus rules.
Multiply the numbers.
3 x 2 = 6
There is no hard and fast rule to select the class width. It largely depends on our application.However, one thing that should be kept in mind is that the number of classes should neither to be too low nor too high. So keeping this thing in mind, the class width is select.
The range of the data is = Maximum- Minimum = 96 - 11 = 85
10 classes will be most suited for this data.
The class width for each data can be calculated as:
Class Width = Range / Number of Classes = 85/10 = 8.5
Class width is always rounded to nearest next integer. So the class width will be 9 in this case.
So, the best value of class width or interval width for the given data will be 9.
Answer:
42+30=72
7+5=12
72-12=60
Blank=60
Step-by-step explanation:
