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kodGreya [7K]
3 years ago
9

Which is the equation in slope intercept form for the line that passes through (-3,3) and is parallel to 3x + y= 7?

Mathematics
2 answers:
Helga [31]3 years ago
3 0

Answer: B

See how I get

Juliette [100K]3 years ago
3 0

Answer:

B y= 1/3x y = 4

explanation:

I just took the quiz for this :>

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What is the value of n in the equation (1)/(2)(n-4)-3=3-(2n+3)
Pavel [41]

(1/2)(n-4)-3=3-(2n+3)

n = 2

but if it is

(n-4)-3=3-(2n+3)

n = 7/3

5 0
2 years ago
Please help I don't understand!
coldgirl [10]

Answer:

AB

Step-by-step explanation:

I believe because on the other side it is AE over ED so I just repeated the pattern.

6 0
2 years ago
find the parametric equations for the line of intersection of the two planes z = x + y and 5x - y + 2z = 2. Use your equations t
Kaylis [27]

Answer:

You didn't give the points in which you want the parametric equations be filled, but I have obtained the parametric equations, and they are:

x = (1/3 + t)

y = (-1/3 - 7t)

z = -6t

Step-by-step explanation:

If two planes intersect each other, the intersection will always be a line.

The vector equation for the line of intersection is given by

r = r_0 + tv

where r_0 is a point on the line and v is the vector result of the cross product of the normal vectors of the two planes.

The parametric equations for the line of intersection are given by

x = ax, y = by, and z = cz

where a, b and c are the coefficients from the vector equation

r = ai + bj + ck

To find the parametric equations for the line of intersection of the planes.

x + y - z = 0

5x - y + 2z = 2

We need to find the vector equation of the line of intersection. In order to get it, we’ll need to first find v, the cross product of the normal vectors of the given planes.

The normal vectors for the planes are:

For the plane x + y - z = 0, the normal vector is a⟨1, 1, -1⟩

For the plane 5x - y + 2z = 2, the normal vector is b⟨5, -1, 2⟩

The cross product of the normal vectors is

v = a × b =

|i j k|

|1 1 -1|

|5 -1 2|

= i(2 - 1) - j(2 + 5) + k(-1 - 5)

= i - 7j - 6k

v = ⟨1, -7, -6⟩

We also need a point on the line of intersection. To get it, we’ll use the equations of the given planes as a system of linear equations. If we set z = 0 in both equations, we get

x + y = 0

5x - y = 2

Adding these equations

5x + x + y - y = 2 + 0

6x = 2

x = 1/3

Substituting x = 1/3 back into

x + y = 0

y = -1/3

Putting these values together, the point on the line of intersection is

(1/3, -1/3, 0)

r_0= (1/3) i - (1/3) j + 0 k

r_0​​ = ⟨1/3, -1/3, 0⟩

Now we’ll plug v and r_0​​ into the vector equation.

r = r_0​​ + tv

r = (1/3)i - (1/3)j + 0k + t(i - 7j - 6k)

= (1/3 + t) i - (1/3 + 7t) j - 6t k

With the vector equation for the line of intersection in hand, we can find the parametric equations for the same line. Matching up r = ai + bj + ck with our vector equation,

r = (1/3 + t) i + (-1/3 - 7t) j + (-6t) k

a = (1/3 + t)

b = (-1/3 - 7t)

c = -6t

Therefore, the parametric equations for the line of intersection are

x = (1/3 + t)

y = (-1/3 - 7t)

z = -6t

3 0
3 years ago
The older floppy diskettes measured 5 and 1/4 inches on each side. What was the diagonal length of the diskette to the nearest t
adoni [48]

Answer:

the answer is 7.4

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
If |a+3|=4 which describes all possible values of a)​
Keith_Richards [23]

Answer:

1 and -1

Step-by-step explanation:

The absolute value means that the answer will always come out as positive, meaning that both 1 and -1 fit in this equation.  

5 0
3 years ago
Read 2 more answers
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