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Minchanka [31]
2 years ago
5

I don't understand this question can someone help me with this please, please explain!! and thank you for the help!! If u dont k

now try your best. Please do it quick, please do all :D

Mathematics
1 answer:
Gekata [30.6K]2 years ago
6 0

Answer:

1. C) .4

2. B) 2 1/4

3. D) 3 5/8

Step-by-step explanation:

1. The question is asking what fraction (represented in decimal form) did Maria spend. To find this, divide 18/45 because Maria spent $18 of her $45. When you complete this calculation, you get .4

2. When you look at where the line ends, it's at the first quarter line after the 2, meaning that the line is 2 and one quarter or 2 1/4

3. 8 times 3 is 24, which is the closest multiple of 8 to 29. However, since there is still 5 left over (which still needs to be divided by 8) it would be represented by the mxed fraction.

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Fiona has $18 to spend. She spent $4.25, including tax, to buy a notebook. She needs to save $9.75, but she wants to buy a snack
prohojiy [21]
18-4.25=13.75$ she has. 13.75-9.75=4$ she can spend. 4$/0.50=8 packages she can buy
3 0
3 years ago
Can someone please help with this problem
notsponge [240]

Answer:

31 degrees

Step-by-step explanation:

well each three point of a triangle equals 180

so 20+35= 55   180-55= 125

now if the exterior angle is 156 and it should equal 180 the interior angle would be 24 degrees

now we have 24 and 125 so angle ? = 31

4 0
3 years ago
Write an equation in point-slope form for the line that passes through
maria [59]

Answer:

y+2=3(x+1)

Step-by-step explanation:

y-(-2)=3(x-(-1))

y+2=3(x+1)

8 0
3 years ago
Given a population mean of 53.7 with a standard deviation of 1.3 and a sample size
a_sh-v [17]

Answer: A. 0.4899 B. 14

Step-by-step explanation:

If X = random variable

then, the standard deviation of the sampling distribution of X = \dfrac{\sigma}{\sqrt{n}}

A.

GIven: \sigma= 1.2, \n= 6

The standard deviation of the sampling distribution of X = \dfrac{1.2}{\sqrt{6}}=0.4899

B. Let n be the sample size,

0.325=\dfrac{1.2}{\sqrt{n}}\\\\\Rightarrow\ \sqrt{n}=\dfrac{1.2}{0.325}\\\\\Rightarrow\ \sqrt{n}=3.69230769231\\\\\Rightarrow\ n= (3.69230769231)^2=13.6331360947\approx 14

Hence, the required sample size = 14

3 0
3 years ago
Select the pair of slopes that are the slopes of perpendicular lines.
agasfer [191]
<h3>\frac{3}{4}\ and\ \frac{-4}{3} are the slopes of perpendicular lines</h3>

<em><u>Solution:</u></em>

We know that,

Product of slope of a line and slope of line perpendicular to it is always equal to -1

<em><u>Option 1</u></em>

\frac{1}{2}\ and\ 2

Product = \frac{1}{2} \times 2 = 1

Thus, these are not the slopes of perpendicular lines

<em><u>Option 2</u></em>

\frac{3}{4}\ and\ \frac{-4}{3}\\\\Product = \frac{3}{4} \times \frac{-4}{3}\\\\Product = -1

This option satisfies the slopes of perpendicular lines

<em><u>Option 3</u></em>

\frac{-2}{5}\ and\ \frac{-5}{2}\\\\Product = \frac{-2}{5} \times \frac{-5}{2} = 1

Thus, these are not the slopes of perpendicular lines

<em><u>Option 4</u></em>

2 and 2

Product = 2 x 2 = 4

Thus, these are not the slopes of perpendicular lines

7 0
3 years ago
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