Implicit defferentation
remember that dy/dx y= dy/dx
so
take derivitive of both sides
![2x+2y \space\ \frac{dy}{dx}=0](https://tex.z-dn.net/?f=2x%2B2y%20%5Cspace%5C%20%5Cfrac%7Bdy%7D%7Bdx%7D%3D0)
solve for
![\frac{dy}{dx}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D)
minus 2x both sides
![2y \space\ \frac{dy}{dx}=-2x](https://tex.z-dn.net/?f=2y%20%5Cspace%5C%20%5Cfrac%7Bdy%7D%7Bdx%7D%3D-2x)
divide both sides by 2y
![\frac{dy}{dx}=\frac{-2x}{2y}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%5Cfrac%7B-2x%7D%7B2y%7D)
![\frac{dy}{dx}=\frac{-x}{y}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%5Cfrac%7B-x%7D%7By%7D)
when is the slope equal to
![\frac{5}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B12%7D)
solve for
![\frac{dy}{dx}=\frac{5}{12}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%5Cfrac%7B5%7D%7B12%7D)
![\frac{dy}{dx}=\frac{5}{12}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%5Cfrac%7B5%7D%7B12%7D)
![\frac{5}{12}=\frac{-x}{y}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B12%7D%3D%5Cfrac%7B-x%7D%7By%7D)
![5y=-12x](https://tex.z-dn.net/?f=5y%3D-12x)
![y=\frac{-12}{5}x](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-12%7D%7B5%7Dx)
find where the circle and this line intersects
substitute
![\frac{-12}{5}x](https://tex.z-dn.net/?f=%5Cfrac%7B-12%7D%7B5%7Dx)
for y
![x^2+(\frac{-12}{5}x)^2=676](https://tex.z-dn.net/?f=x%5E2%2B%28%5Cfrac%7B-12%7D%7B5%7Dx%29%5E2%3D676)
![x^2+\frac{144}{25}x^2=676](https://tex.z-dn.net/?f=x%5E2%2B%5Cfrac%7B144%7D%7B25%7Dx%5E2%3D676)
![\frac{25}{25}x^2+\frac{144}{25}x^2=676](https://tex.z-dn.net/?f=%5Cfrac%7B25%7D%7B25%7Dx%5E2%2B%5Cfrac%7B144%7D%7B25%7Dx%5E2%3D676)
![\frac{169}{25}x^2=676](https://tex.z-dn.net/?f=%5Cfrac%7B169%7D%7B25%7Dx%5E2%3D676)
times both sides by
![\frac{25}{169}](https://tex.z-dn.net/?f=%5Cfrac%7B25%7D%7B169%7D)
![x^2=100](https://tex.z-dn.net/?f=x%5E2%3D100)
sqrt both sides, take positive and negative roots
x=+/-10
sub back
![y=\frac{-12}{5}x](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-12%7D%7B5%7Dx)
![y=(\frac{-12}{5})(10) \space\ or \space\ (\frac{-12}{5})(-10)](https://tex.z-dn.net/?f=y%3D%28%5Cfrac%7B-12%7D%7B5%7D%29%2810%29%20%5Cspace%5C%20or%20%5Cspace%5C%20%28%5Cfrac%7B-12%7D%7B5%7D%29%28-10%29%20)
![y=\frac{-120}{5} \space\ or \space\ \frac{120}{5}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-120%7D%7B5%7D%20%5Cspace%5C%20or%20%5Cspace%5C%20%5Cfrac%7B120%7D%7B5%7D%20)
![y=-24 \space\ or \space\ 24](https://tex.z-dn.net/?f=y%3D-24%20%5Cspace%5C%20or%20%5Cspace%5C%2024%20)
the points are (10,-24) and (-10,24)
You ran 4.64 km altogether
Step-by-step explanation:
If you go for a run on Monday and manage to run 2.32 km and the on Tuesday you run the same distance, then that would be another 2.32 km ran on Tuesday. We can then add these two together to figure out your Total distance ran altogether in those 2 days.
I assume the sentences:
"23 employees speak German; 29 speak French; 33 speak Spanish"
mean these speak ONLY the respective languages other than English.
Then the calculations boil down to those who speak ONLY two languages, noting that 8 speak French, German and Spanish, which need to be subtracted from
1. French and Spanish: 43-8=35 (speak only two foreign languages)
2. German and French: 38-8=30 (speak only two foreign languages)
3. German and Spanish: 48-8=40 (speak only two foreign languages).
Now We add up the total number of employees:
zero foreign language = 7
one foreign language = 23+29+33=85
two foreign languages = 30+35+40=105
three foreign languages=8
Total =7+85+105+8=205
(a) Percentage of employees who speak at least one foreign lanugage = (85+105+8)/205=198/205=.966=96.6%
(b) Percentage of employees who speak at least two foreign lanugages = (105+8)/205=113/205=.551=55.1%
Answer: Mrs. Alberts spent $1,050 on the floor.
Step-by-step explanation: First lets find the area to get the total amount of square feet by multiply length by width.
12.5 x 7 = 87.5 square ft.
We know that it costs $12 per square foot, and we have 87.5 square feet.
So, multiply 12 by 87.5 to find the cost that Mrs, Alberts will spend on the floor.
12 x 87.5 = 1050, or $1,050 for the total area of the floor.