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wolverine [178]
3 years ago
8

The class sizes of elementary school classes in a public school district are normally distributed with an unknown population mea

n and standard deviation. A random sample of 27 classes is taken and results in a sample mean of 20 students and sample standard deviation of 6 students. The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution is 2.86. Find a 98% confidence interval estimate for the population mean using the Student's t-distribution.
Mathematics
1 answer:
weqwewe [10]3 years ago
8 0

Answer: (17.14,\ 22.86)

Step-by-step explanation:

The confidence interval estimate for the population mean is given by :-

\overline{x}\pm ME, where \overline{x} is the sample mean and ME  is the margin of error.

Given : Sample mean: \overline{x}=20

The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution : ME=2.86

Now, the confidence interval estimate for the population mean will be :-

20\pm2.86=(20-2.86,\ 20+2.86)=(17.14,\ 22.86)

Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution =  (17.14,\ 22.86)

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Keywords: Solving expressions

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