The class sizes of elementary school classes in a public school district are normally distributed with an unknown population mea
1 answer:
Answer:
Step-by-step explanation:
The confidence interval estimate for the population mean is given by :-
, where
is the sample mean and ME is the margin of error.
Given : Sample mean:
The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution :
Now, the confidence interval estimate for the population mean will be :-
Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution =
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Answer:
59 to 66
Step-by-step explanation:
Mean test scores = u = 74.2
Standard Deviation = = 9.6
According to the given data, following is the range of grades:
Grade A: 85% to 100%
Grade B: 55% to 85%
Grade C: 19% to 55%
Grade D: 6% to 19%
Grade F: 0% to 6%
So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.
6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)
The formula for z score is:
For z = -1.56, we get:
For z = -0.88, we get:
Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)
Answer:
(5 square root 2-4 square root 3) (5 square root 2-4 square root 3)
= 98 - 40
Step-by-step explanation:
i) (5 - 4
) × (5√2 - 4√3)
=(5 × 5
) - (5
× 4
) - (4
× 5
) + (4
× 4
)
= 50 - 20 - 20
+ 48
= 98 - 40