1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yawa3891 [41]
2 years ago
8

Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
6 0

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

You might be interested in
Help... anyone i just need help with these questions!?!
anyanavicka [17]
For the first one it is
4 0
3 years ago
Read 2 more answers
A 10-foot ladder is leaning against a tree. The bottom of the ladder is 4 feet away from the bottom of the tree. Approximately h
strojnjashka [21]

Answer:

C

Step-by-step explanation:

If we were to draw a horizontal line from the bottom of the ladder to the bottom of the tree and then draw a vertical line from the bottom of the tree to the top of the ladder, we'd get a right triangle with legs as the distance between the bottom of the tree and the bottom of the ladder and the height of the ladder, and the hypotenuse is the length.

Here, we know the hypotenuse is 10 feet and that the bottom of the ladder is 4 feet away from the bottom of the tree, so use the Pythagorean Theorem to find the height:

h = \sqrt{10^2-4^2} =\sqrt{84} ≈ 9.2 feet

The answer is C.

7 0
3 years ago
Read 2 more answers
A box is filled with 7 brown cards, 3 yellow cards, and 8 red cards. A card is chosen at random from the box. What is the probab
Deffense [45]
7 brown, 3 yellow, 8 red...total of 18 cards

there are 15 cards not yellow and a total of 18 cards....so the probability of not picking a yellow card is : 15/18 rounds to 5/6
3 0
3 years ago
How to do this pls:( using PEMDAS
Kryger [21]

Answer: x y

-2 15

-1 9

0 7

1 9

2 15

3 25

Step-by-step explanation:you always do the exponent first, then you multiply that by that two, and then you add 7.

7 0
3 years ago
Please help me solve this, I will give you brainliest
ehidna [41]

2008 payan walang yan ha kaya mo yan

7 0
3 years ago
Other questions:
  • Two integers that vary in sign
    8·2 answers
  • How do i find the slope
    10·1 answer
  • What is the faction 5/6 as a product of a whole number and a unit fraction
    11·1 answer
  • Solve for x<br> -x + 5 + 6x = 1 + 5x + 3
    7·1 answer
  • Is 0.71711... a rational number or irrational?
    8·2 answers
  • Which of the following values is a solution of 12.6 = 3x?
    9·2 answers
  • Question is the attached file.
    10·1 answer
  • Please help me out on this.
    9·1 answer
  • What is the answer need it
    7·1 answer
  • A closed container has 2.04 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10−24 grams. Which of the following shows
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!