T = days passed
r = rate of growth
by 0 day, or t = 0, there are 2 folks sick,

by the third day, t = 3, there are 40 folks sick,
![\bf \qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\to &40\\ P=\textit{initial amount}\to &2\\ r=rate\to r\%\to \frac{r}{100}\\ t=\textit{elapsed time}\to &3\\ \end{cases} \\\\\\ 40=2(1+r)^3\implies 20=(1+r)^3\implies \sqrt[3]{20}=1+r \\\\\\ \sqrt[3]{20}-1=r\implies 1.7\approx r\qquad \boxed{A=2(2.7)^t}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BAmount%20for%20Exponential%20Growth%7D%0A%5C%5C%5C%5C%0AA%3DP%281%20%2B%20r%29%5Et%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5Cto%20%2640%5C%5C%0AP%3D%5Ctextit%7Binitial%20amount%7D%5Cto%20%262%5C%5C%0Ar%3Drate%5Cto%20r%5C%25%5Cto%20%5Cfrac%7Br%7D%7B100%7D%5C%5C%0At%3D%5Ctextit%7Belapsed%20time%7D%5Cto%20%263%5C%5C%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0A40%3D2%281%2Br%29%5E3%5Cimplies%2020%3D%281%2Br%29%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B20%7D%3D1%2Br%0A%5C%5C%5C%5C%5C%5C%0A%5Csqrt%5B3%5D%7B20%7D-1%3Dr%5Cimplies%201.7%5Capprox%20r%5Cqquad%20%5Cboxed%7BA%3D2%282.7%29%5Et%7D)
how many folks are there sick by t = 6?
It would be $7.50 because 4 ounces equals $1 so 30/4 =7.5
Answer:
See explanation
Step-by-step explanation:
1 step:
n=1, then

So, for j=1 this statement is true
2 step:
Assume that for n=k the following statement is true

3 step:
Check for n=k+1 whether the statement

is true.
Start with the left side:

According to the 2nd step,

Substitute it into the 

So, you have proved the initial statement
We need to determine the term life insurance amount per thousand on a 22-year-old female for a 5-year policy given that the face value of the policy is $600,000 and the annual premium is $1332.
Since we are supposed to find the term life insurance amount per thousand, therefore, we will use the following formula:

Upon substituting the values of annual premium and face value of insurance, we get:

Therefore, the required life insurance amount is $2.22.
The arc length of the circle is 5π/9 units
<h3>How to determine the arc length?</h3>
From the question, we have the following parameters
Angle, ∅ = 5π/9
Radius, r = 1 unit
The arc length (x) is calculated as
x = r∅
Substitute the known values in the above equation
x = 5π/9 * 1
Evaluate the product
x = 5π/9
Hence, the arc length of the circle is 5π/9 units
Read more about arc lengths at:
brainly.com/question/2005046
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