Answer:
57.93%
Step-by-step explanation:
We have been given that men have head breadths that are normally distributed with a mean of 6.0 inches and a standard deviation of 1.0 inches. We are asked to find the probability that a man's breadth is less than 6.2 inches.
First of all, we will find z-score corresponding to sample score of 6.2 as:
, where,
z = Z-score,
x = Sample score,
= Mean,
= Standard deviation.
Upon substituting our given values in z-score formula, we will get:



Now, we need to find the probability that a z-score is less than 0.2.
Using normal distribution table, we will get:


Therefore, the probability that a male's head breadth is less than 6.2 inches, would be approximately 57.93%.
Step-by-step explanation:
c²= 8²+6²
c²= 64+36
c²=100
c=10
509 people.


you can't have 0.094 of someone so we round the answer off the 509.
Your answer is 8/5
If you plug it in, you get:
8/(2+3)
Add the 2 and 3 and you’ll get
8/5