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bazaltina [42]
3 years ago
8

After going through this module, you are expected to:

Mathematics
2 answers:
Svetach [21]3 years ago
7 0

Answer:

See below

Step-by-step explanation:

<u>Number of squares:</u>

  • 1x1 squares = 8*8
  • 2x2 squares  = 7*7
  • 3x3 squares  = 6*6
  • 4x4 squares  = 5*5
  • 5x5 squares  = 4*4
  • 6x6 squares  = 3*3
  • 7x7 squares  = 2*2
  • 8x8 square  = 1

<u>Total number:</u>

  • 8² + 7² + 6² + 5² + 4² + 3² + 2² + 1 =
  • 64 + 49 + 36 + 25 + 16 + 9 + 4 + 1 =
  • 204
Ronch [10]3 years ago
7 0

squares numbers:

1x1 squares = 8*8

2x2 squares  = 7*7

3x3 squares  = 6*6

4x4 squares  = 5*5

5x5 squares  = 4*4

6x6 squares  = 3*3

7x7 squares  = 2*2

8x8 square  = 1

number total:

8² + 7² + 6² + 5² + 4² + 3² + 2² + 1 =

64 + 49 + 36 + 25 + 16 + 9 + 4 + 1 =

204

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Solve for x:<br> X=<br> 76⁰<br> 9x+1<br> 40°
luda_lava [24]

7 is the value of x, and 64° is the measure of the unknown angle.

Triangle angles of 76°, (9x+1)°, and 40° are provided.

According to the triangle's "angle sum property," a triangle's angles add up to 180 degrees. Three sides and three angles, one at each vertex, make up a triangle. The sum of the interior angles in a triangle is always 180o, regardless of whether it is acute, obtuse, or right.

One of the most commonly applied properties in geometry is the triangle's angle sum property. Most often, the unknown angles are calculated using this attribute.

Now, the total of a triangle's three angles equals

76°+(9x+1)°+40°= 180°

⇒ 116+9x+1 = 180

⇒ 9x + 117 = 180

⇒ 9x = 63

⇒ x = 7

So, 9x+1=64°

As a result, x is equal to 7 and the unmeasured angle is 64°.

To learn more about the angle sum property of a triangle, refer to this link:

brainly.com/question/8492819

#SPJ1

4 0
9 months ago
Solve the inequality
const2013 [10]
X < -11/9 is the answer

4 0
3 years ago
Mary has five-eighths of the total of pencils her and her sister own. Together, they have 96 pencils. How many pencils does Mary
olga55 [171]
60 pencils. It’s a ratio. 60/96 can be simplified down to 5/8
5 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
I need help on this question
tester [92]
A i guess i just need points
8 0
3 years ago
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