<u>Answer:</u> The moles of silver nitrate reacted is 5.72 moles, moles of iron (II) nitrate produced is 2.86 moles and moles of silver chloride produced is 5.72 moles
<u>Explanation:</u>
We are given:
Moles of iron (II) chloride = 2.86 moles
For the given chemical equation:

- <u>For silver nitrate:</u>
By Stoichiometry of the reaction:
1 mole of iron (II) chloride reacts with 2 moles of silver nitrate.
So, 2.86 moles of iron (II) chloride will react with =
of silver nitrate
Moles of silver nitrate reacted = 5.72 moles
- <u>For iron (II) nitrate:</u>
By Stoichiometry of the reaction:
1 mole of iron (II) chloride produces 1 mole of iron (II) nitrate
So, 2.86 moles of iron (II) chloride will produce =
of iron (II) nitrate
Moles of iron (II) nitrate produced = 2.86 moles
- <u>For silver chloride:</u>
By Stoichiometry of the reaction:
1 mole of iron (II) chloride produces 2 moles of silver chloride
So, 2.86 moles of iron (II) chloride will produce =
of silver chloride
Moles of silver chloride produced = 5.72 moles
Hence, the moles of silver nitrate reacted is 5.72 moles, moles of iron (II) nitrate produced is 2.86 moles and moles of silver chloride produced is 5.72 moles