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aliya0001 [1]
3 years ago
5

The pH scale for acidity is defined by pH=−log10[H⁺] where [H⁺]is the concentration of hydrogen ions measured in moles per liter

(M). A solution has a pH of 12.25. Calculate the concentration of hydrogen ions in moles per liter (M). The concentration of hydrogen ions is ___________ moles per liter.
Chemistry
1 answer:
masha68 [24]3 years ago
7 0

Answer:

5.62 * 10^-13 moles per liter

Explanation:

The pH of a solution is the negative logarithm to base 10 of the concentration of hydrogen ions. What we simply do here is to input the information in the question into the equation:

pH=−log10[H⁺]

Here we know the pH but we do not know the concentration of the hydrogen ions.

12.25 = -log [H+]

log[H+] = -12.25

[H+] = 10^-12.25

[H+] = 5.62 * 10^-13 moles per liter

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Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and pK_{a} is as follows.

               pH = pK_{a} + log \frac{base}{acid}

where,     pH = 7.4 and pK_{a} = 7.21

As here, we can use the pK_{a} nearest to the desired pH.

So,      7.4 = 7.21 + log \frac{base}{acid}

             0.19 = log \frac{base}{acid}

            \frac{base}{acid} = 1.55

1 mM phosphate buffer means [HPO_{4}] + [H_{2}PO_{4}] = 1 mM

Therefore, the two equations will be as follows.

           \frac{HPO_{4}}{H_{2}PO_{4}} = 1.55 ............. (1)

  [HPO_{4}] + [H_{2}PO_{4}] = 1 mM ........... (2)        

Now, putting the value of [HPO_{4}] from equation (1) into equation (2) as follows.

             1.55[H_{2}PO_{4}] + [tex][H_{2}PO_{4}] = 1 mM

                        2.55 [H_{2}PO_{4}] = 1 mM

                             [H_{2}PO_{4}] = 0.392 mM

Putting the value of [H_{2}PO_{4}] in equation (1) we get the following.

                     0.392 mM + [HPO_{4}] = 1 mM

                          [HPO_{4}] = (1 - 0.392) mM

                              [HPO_{4}] = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0
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Heterozygous- a person having two different alleles for a gene is also called
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A genotype consisting of two different alleles of a gene for a particular trait (Aa). Individuals who are heterozygous for a trait are referred to as heterozygotes.

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Answer:

m=7.07gH_{2}SO_{4}

Explanation:

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1840\frac{g}{L}

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d=\frac{m}{V}

Solving for m:

m=\frac{V}{d}

3. Replace values:

m=\frac{1.30*10^{4}L}{1840\frac{g}{L}}

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3 years ago
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