Examining the given reaction:
Li2O + H2O ........> 2LiOH
we find that, 1 mole of Li2O is required to react with one mole of H2O in order to produce two moles of LiOH.
Therefore, the ration between the required Li2O and H2O is 1:1
Based on this, 2.2 moles of H2O (water) are required to react with 2.2 moles of Li2O
11×2=22
(11×2)+(6)+(8×3)=52
22/52=0.4230
0.4230×100=42.3%
<span>362.51 Kelvin
ln (p1/p2) =( dH / R) (1/T2 - 1/T1)
ln (760 Torr /520Torr) =( 40,700 Joules / 8.314 J molâ’1K-1)(1/T2 - 1/373K)
ln (1.4615) =( 4895.35)(1/T2 - 0.002681)
0.37946 = 4895.35/T2 - (0.002681)(4895.35)
0.37946 = 4895.35/T2 - (13.124)
0.37946 + 13.124 = 4895.35/T2
13.5039 = 4895.35/T2
T2 = 4895.35 / 13.5039
T2 = 362.51
answer is 362.51 Kelvin
- 273
answer is also 89.5 Celsius</span>
Answer:
I think the answer is boiling