PV=nRT
Here
P1/T1= P2 / T2
1 torr=133 pascal
600 *133 /215 = 750 *133 / t2
T2= 268.75 K
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The specific heat in, J /g °C of copper is 0.386J/g°C
HOW TO CALCULATE SPECIFIC HEAT CAPACITY OF A SUBSTANCE:
- The specific capacity of a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or released (J)
m = mass of substance (g)
∆T = change in temperature (°C)
c = specific heat capacity (J/g°C)
For a colorimeter, the following equation applies:
m.c.∆T (water) = - m.c.∆T (metal)
m = 50g
c = 4.184 J/g°C
∆T = 29.2 - 26°C = 3.2°C
m = 70g
c = ?
∆T = 29.2 - 54°C = -24.8°C
m.c.∆T (water) = - m.c.∆T (metal)
50 × 4.184 × 3.2 = -(70 × c × -24.8)
669.44 = 1736c
c = 669.44 ÷ 1736
c = 0.386J/g°C
Therefore, the specific heat in, J /g °C of copper is 0.386J/g°C
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<span>Consider the balanced equation below.
2H2S + 3O2 ---> 2SO2 + 2H2O
Which option gives the correct mole ratios?
H2S:SO2 = 2:2 and O2:H2O = 3:2
H2S:SO2 = 2:3 and O2:H2O = 3:2
H2S:SO2 = 4:4 and O2:H2O = 5:4
H2S:SO2 = 4:6 and O2:H2O = 4:4</span>
is the aswer H2S:SO2=2:2 and O2:H2O=3:2
Answer:
C: metals donate electrons to non metals
Explanation: