Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Answer:
Step-by-step explanation:
Newton's Second Law: Force on a body is equal to the product of mass and acceleration of the centre of the mass of the body.
Initially:
At the end of the road:
Step-by-step explanation:
4x + 7x + 2° = 90° { being complementary angles }
11x = 90° - 2°
11x = 88°
x = 88° / 11
x = 8°
<YVZ = <em>7</em><em> </em><em>*</em><em> </em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>2</em><em>°</em><em> </em><em>=</em><em> </em><em>5</em><em>8</em><em>°</em>
<em>Hope </em><em>it </em><em>will </em><em>help </em><em>:</em><em>)</em>
Answer:
Center at (4, 7) and radius is √49, or 7
Step-by-step explanation:
Didn't you mean (x-4)² + (y-7) ² = 49?
Comparing (x-4)² + (y-7) ² = 49
to (x - h)^2 + (y - k)^2 = r^2, we see that the center is at (h, k) => (4, 7) and that the radius is √49, or 7.
