Two lines intersect in one point. True or False

Why would some states be unwilling to integrate their schools? Give two reasons for full credit.

Dimas [21]

Answer:

State legislatures passed bills to thwart desegregation through “freedom-of-choice plans, which allowed parents to choose among several schools; transfer options, which permitted parents to move their children out of integrated schools; and grade-a-year plans, which started desegregation in the first or twelfth grade

8 0

2 years ago

Read 2 more answers

What is 328.618 round to the nearest hundredth A. 300 B. 328.60 C. 330 D. 328.62

son4ous [18]

Answer:

D. 328.62

Step-by-step explanation:

328.618 round to the nearest hundredth

Rounding to the nearest hundredth means 2 numbers after the decimal point

Numbers that rounds to 1 are 5, 6, 7, 8, 9

Number that rounds to 0 are 0, 1, 2, 3, 4

When rounding up, to the nearest hundredth, you will consider the next number after the two figures after the decimal point

Here, the next number after the two figures after the decimal point is 8

8 is a number that rounds to 1

Therefore, add 1 to 1 to have

328.62

4 0

2 years ago

Which comparison is not correct?

Elden [556K]

Answer:

it’s the third one

Step-by-step explanation:negatives are never higher than numbers without negatives

7 0

3 years ago

67% of owned dogs in the United States are spayed or neutered. Round your answers to four decimal places. If 48 owned dogs are r

oksian1 [2.3K]

Answer:

a) Probability that exactly 29 of them are spayed or neutered = 0.074

b) Probability that at most 33 of them are spayed or neutered = 0.66

c) Probability that at least 30 of them are spayed or neutered = 0.79

d) Probability that between 28 and 33 (including 28 and 33) of them are spayed or neutered = 0.574

Step-by-step explanation:

This is a binomial distribution question

probability of having a spayed or neutered dog, p = 0.67

probability of having a dog that is not spayed or neutered, q = 1 - 0.67

q = 0.23

sample size, n = 48

According to binomial distribution formula:

$P(X=r) = nCr p^r q^{n-r}$

where $nCr = \frac{n!}{(n-r)! r!}$

a) Probability that exactly 29 of them are spayed or neutered

$P(X= 29) = 48C29 * 0.67^{29} * 0.23^{19}\\P(X=29) = 0.074$

b) Probability that at most 33 of them are spayed or neutered

$P(X \leq 33) =1 - P(X > 33)\\P(X \leq 33) =1 - 0.34\\P(X \leq 33) = 0.66$

c) Probability that at least 30 of them are spayed or neutered

$P(X \geq 30) = 1 - P(x < 30)\\P(X \geq 30) = 1 - 0.21\\P(X \geq 30) = 0.79$

d) Probability that between 28 and 33 (including 28 and 33) of them are spayed or neutered.

$P(28 \leq X \leq 33) = P(X=28) + P(X=29) + P(X=30) + P(X=31) + P(X=32) + P(X=33)\\P(28 \leq X \leq 33) = 0.053 + 0.074 + 0.095 + 0.112 + 0.121 + 0.119\\P(28 \leq X \leq 33) = 0.574$

8 0

2 years ago

Please help Look at picture Supplementary angles

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

$3)\frac{5x}{2}+125 = 180\\\\\frac{5x}{2}=180-125\\\\\frac{5x}{2}=55\\\\ 5x = 55*2\\\\ x =\frac{55*2}{5}\\\\ x = 11*2 = 22$

4) 3x+ 42 + 90= 180

3x + 132 = 180

3x = 180 -132

3x = 48

x = 48/3

x = 16

8 0

2 years ago