All categories

4 years ago

Which comparison is not correct?

Mathematics

1 answer:

Elden [556K]4 years ago

7 0

Answer:

it’s the third one

Step-by-step explanation:negatives are never higher than numbers without negatives

You might be interested in

You invest $2000 in an account at 4.5% per year simple interest. How much will you have in the account at the beginning of the 8

77julia77 [94]

I will have $2721 at the beginning of the eighth year.

The beginning of the eighth year is the end of seven years of investing.

The formula for the future value (FV) of my investment is

FV = C(1 + r)^n

where C = my initial cash

r = the interest rate

n = the number of years

FV = $2000(1.045)^7 = $2722

8 0

3 years ago

Determine the measure of angle A

Vinil7 [7]

Step-by-step explanation:

3x+18=4x+2

x= 16

measure of <A = 66°

8 0

3 years ago

Change 2.33 to a simplified fraction. Round to the nearest hundredth.

Butoxors [25]

Answer: 233.00

Step-by-step explanation: In this case, Rule I applies, so 233/1 (or 233.000) rounded to the nearest hundredth in decimal format is:

8 0

3 years ago

Find the average of 2 and 4.

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

2+4=6 6/2=3

7 0

3 years ago

Read 2 more answers

Solve to find x log (3x+5) to base 5= 2log (1-3x) to base 25

Eduardwww [97]

Answer:

x = -2/ 3

Step-by-step explanation:

in order to cancel out the logs they should have common bases

$\mathsf{ log_{5}(3x + 5) = 2 log_{25}(1 - 3x) }$

we can write 25 as 5²

$\mathsf{ \implies log_{5}(3x + 5) = 2 \: log_{ {5}^{2} }(1 - 3x) }$

we know that the reciprocal of the exponents of the bases are multiplied to the log

$\mathsf{ \implies log_{5}(3x + 5) = \frac{1}{\cancel{2} } \times \cancel{2} \: log_{ 5}(1 - 3x) }$

and now since the logs have common bases

$\mathsf{ \implies \cancel { log_{5}}(3x + 5) = \cancel{ log_{ 5}}(1 - 3x) }$

we're left with

$\mathsf{ \implies 3x + 5 = 1 - 3x}$

$\mathsf{ \implies 9x = -4}$

x = -2/ 3

8 0

3 years ago