Answer:
a) Probability that exactly 29 of them are spayed or neutered = 0.074
b) Probability that at most 33 of them are spayed or neutered = 0.66
c) Probability that at least 30 of them are spayed or neutered = 0.79
d) Probability that between 28 and 33 (including 28 and 33) of them are spayed or neutered = 0.574
Step-by-step explanation:
This is a binomial distribution question
probability of having a spayed or neutered dog, p = 0.67
probability of having a dog that is not spayed or neutered, q = 1 - 0.67
q = 0.23
sample size, n = 48
According to binomial distribution formula:

where 
a) Probability that exactly 29 of them are spayed or neutered

b) Probability that at most 33 of them are spayed or neutered

c) Probability that at least 30 of them are spayed or neutered

d) Probability that between 28 and 33 (including 28 and 33) of them are spayed or neutered.
