Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500
Answer:
this is a type habitat or ecosystem
Explanation:
This is a True Statement.HOPE IT HELPED YOU
This sums up most of them
