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3 years ago

Simplify the square root of 32/5

1 answer:

3 0

Remember $\sqrt{ \frac{x}{y} } = \frac{ \sqrt{x} }{ \sqrt{y} }$
and
$\sqrt{ab^2} =b \sqrt{a}$
$\sqrt{ \frac{32}{5} } = \frac{ \sqrt{(4^2)(2)} }{ \sqrt{5} } = \frac{ 4\sqrt{2} }{ \sqrt{5} }$
times whoe thing by $\frac{ \sqrt{5} }{ \sqrt{5} }$
$\frac{4 \sqrt{10} }{5}$

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Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take

Ipatiy [6.2K]

Answer:

a) r = 0.974

b) Critical value = 0.602

Step-by-step explanation:

Given - Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take both test and the results are give below

Test A | 64 48 51 59 60 43 41 42 35 50 45

Test B | 91 68 80 92 91 67 65 67 56 78 71

To find - (a) What is the value of the linear coefficient r ?

(b) Assuming a 0.05 level of significance, what is the critical value ?

Proof -

r = 0.974

Critical Values for the Correlation Coefficient

n alpha = .05 alpha = .01

4 0.95 0.99

5 0.878 0.959

6 0.811 0.917

7 0.754 0.875

8 0.707 0.834

9 0.666 0.798

10 0.632 0.765

11 0.602 0.735

12 0.576 0.708

13 0.553 0.684

14 0.532 0.661

So,

Critical r = 0.602 for n = 11 and alpha = 0.05

6 0

3 years ago

ccording to the U.S. National Weather Service, at any given moment of any day, approximately 1000 thunderstorms are occurring wo

viva [34]

Answer:

The critical value of z for 99% confidence interval is 2.5760.

The 99% confidence interval for population mean number of lightning strike is (7.83 mn, 8.37 mn).

Step-by-step explanation:

Let X = number of lightning strikes on each day.

A random sample of n = 23 days is selected to observe the number of lightning strikes on each day.

The random variable X has a sample mean of, $\bar x=8.1\ mn$ and the population standard deviation, $\sigma=0.51\ mn$ .

The (1 - α)% confidence interval for population mean μ is:

$CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

Compute the critical value of z for 99% confidence interval is:

$z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.5760$

*Use a z-table.

The critical value of z for 99% confidence interval is 2.5760.

Compute the 99% confidence interval for population mean number of lightning strike as follows:

$CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\=8.1\pm2.5760\times\frac{0.51}{\sqrt{23}}\\=8.1\pm0.2738\\=(7.8262, 8.3738)\\\approx(7.83, 8.37)$

Thus, the 99% confidence interval for population mean number of lightning strike is (7.83 mn, 8.37 mn).

The 99% confidence interval for population mean number of lightning strike implies that the true mean number of lightning strikes lies in the interval (7.83 mn, 8.37 mn) with 0.99 probability.

3 0

3 years ago

WHats 100000000000000 x 1000000000000000000000

ser-zykov [4K]

Answer:

1e+35

Step-by-step explanation:

7 0

3 years ago

112.324 nearest tenth

slavikrds [6]

Answer:

112.3

Step-by-step explanation:

112.3 if the 2 was 5 or higher it would be 112.4

5 0

3 years ago

Read 2 more answers

Y= f(x)=2x find f(x) when x=2

mina [271]

According to the problem, y = f(x) = 2x

Here the value of x = 2.

We have to put the value of x in place of x in 2x to calculate the actual value of 2x.

Therefore, after putting the value of x in 2x we get 2x = 2 x 2 = 4

This means the value of 2x is 4. This is because we have included the given value of x to get the value of 2x.

Again the value of f(x) = 2x.

Therefore, the value of f(x) = 2x = 4.

6 0

3 years ago