Question

Write an equation in standard form for the line, where the points (-2, -1) and (0, 4) are on the line

Answer 1

Answer:

An equation in standard form for the line is:

$\frac{5}{2}x-y=-4$

Step-by-step explanation:

Given the points

• (-2, -1) and (0, 4)

The slope between two points

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-2,\:-1\right),\:\left(x_2,\:y_2\right)=\left(0,\:4\right)$

$m=\frac{4-\left(-1\right)}{0-\left(-2\right)}$

$m=\frac{5}{2}$

Writing the equation in point-slope form

As the point-slope form of the line equation is defined by

$y-y_1=m\left(x-x_1\right)$

Putting the point (-2, -1) and the slope m=1 in the line equation

$y-\left(-1\right)=\frac{5}{2}\left(x-\left(-2\right)\right)$

$y+1=\frac{5}{2}\left(x+2\right)$

$y=\frac{5}{2}x+4$

Writing the equation in the standard form form

As we know that the equation in the standard form is

$Ax+By=C$

where x and y are variables and A, B and C are constants

so

$y=\frac{5}{2}x+4$

$\frac{5}{2}x-y=-4$

Therefore, an equation in standard form for the line is:

$\frac{5}{2}x-y=-4$