(1) 2y×5x(7÷18)-1+3?And (2) 45÷28(3x+6y)=
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Applying the formula for each identified shape that are given, the correct areas to each shape are:
a. <em>Square </em>= 134.6 sq. yd
b. <em>Circle </em>= 452.2 sq. cm
c. <em>Parallelogram </em>= 40.6 sq. cm
d. <em>Rectangle </em>= 43.2 sq. ft
e. <em>Trapezium </em>= 25.7 sq. m
f. <em>Triangle</em> = 21.6 sq. ft
a. The shape given is a square.
Area of the square =
Where,
s = 11.6 yd
Plug in the value of s
Area of the square =
b. The shape given is a circle.
Area of the circle =
- Where,
r = 12 cm
- Plug in the value of r
Area of the square =
c. The shape given is a parallelogram.
Area of the parallelogram =
- Where,
b = 7 cm
h = 5.8 cm
- Plug in the value of b and h
Area of the parallelogram =
d. The shape given is a rectangle.
Area of the rectangle =
- Where,
l = 8.3 ft
w = 5.2 ft
- Plug in the value of l and w
Area of the rectangle =
e. The shape given is a trapezium.
Area of the trapezium =
- Where,
a = 2.8 m
b = 10.4 m
h = 3.9 m
- Plug in the value of a, b, and h
Area of the trapezium =
f. The shape given is a triangle. <em>(See attachment for the shape).</em>
Area of the triangle =
- Where,
b = 9 ft
h = 4.8 ft
- Plug in the value of b, and h
Area of the triangle =
Therefore, applying the formula for each identified shape that are given, the correct areas to each shape are:
a. <em>Square </em>= 134.6 sq. yd
b. <em>Circle </em>= 452.2 sq. cm
c. <em>Parallelogram </em>= 40.6 sq. cm
d. <em>Rectangle </em>= 43.2 sq. ft
e. <em>Trapezium </em>= 25.7 sq. m
f. <em>Triangle</em> = 21.6 sq. ft
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Answer:
660 mm
Step-by-step explanation:
we know that
The scale factor is
That means
1 unit in the model represent 15 units in the actual
or
1 m in the model represent 15 m in the actual
To find out the height of the model rocket, divide the height of the actual rocket by 15
so
Convert m to mm
Remember that
To convert meters to millimeters, multiply by 1,000
so