Answer:
![m=-1](https://tex.z-dn.net/?f=m%3D-1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Slope Formula:
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-11, 6)
Point (-7, 2)
<u>Step 2: Find slope </u><em><u>m</u></em>
Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>
- Substitute [SF]:
![m=\frac{2-6}{-7+11}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B2-6%7D%7B-7%2B11%7D)
- Subtract/Add:
![m=\frac{-4}{4}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-4%7D%7B4%7D)
- Divide:
![m=-1](https://tex.z-dn.net/?f=m%3D-1)
Let p(x)=x^3+2x^2+kx+3
On dividing p(x) by x-3, the remainder is 21. Therefore,
P(3)=21
Substituting x=3 in p(x)
P(3)=3^3 +2*(3)^2+k*3+3
=27+18+3k+3
=48+3k
We know that, p(3)=21.
So, 48+3k=21
3k=21-48
3k=-27
k=-27/3 =-9
now, p(x) =x^3+2x^2-9x-18
-2 is a factor of p(x) on inspection. Therefore, divide p(x) by x+2 to find the
zeroes of the polynomial.
On dividing, we get the factors to be, (x^2-9)(x+2)
(x^2-3^2)(x+2)
Factorizing using the identity a^2-b^2=(a+b)(a-b) we get,
(x+3)(x-3)(x+2)
Therefore, the zeroes of the polynomials are -3,+3 and -2.
Slope: 3, y-intercept: 4, equation: y = 3x + 4
Store A price for 1 tulip is 11/5= $2.20
store B price for 1 tulip is 13/6 =$2.17
<span>$8 each month
</span><span>How many months will it take him to save at least $60?
60 </span>÷ 8 = 7.5
It will take Phillip 7.5 months to save up at least $60!