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svp [43]
2 years ago
14

Given sinθ = 2/5 and cosθ < 0: 1. Find cscθ 2. Find cotθ

Mathematics
1 answer:
Tems11 [23]2 years ago
5 0

Recall that

sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1

for all <em>θ</em>, and given that cos(<em>θ</em>) < 0, we find that

cos(<em>θ</em>) = -√(1 - sin²(<em>θ</em>)) = -√(1 - (2/5)²) = -√(21)/5

Now,

csc(<em>θ</em>) = 1/sin(<em>θ</em>) = 1/(2/5) = 5/2

and

cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>) = (-√(21)/5)/(2/5) = -√(21)/2

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3 0
3 years ago
What is the product of 5x10 to the power of 2
ratelena [41]

50^2 = 50 to the power of 2 = 2.5 × 10^3

Explanation:

(50) to the 2nd power or simply '50 to the 2nd' is obtained by multiplying 2 times the base 50 by itself. So,

50^2 = 50 × 50 = 2.5 × 10^3

Note: We say that 50 is the base, 2 is the exponent, and the whole thing or the result is a power of 50.

5 0
3 years ago
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6 0
3 years ago
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Jet001 [13]

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Step-by-step explanation:

8 0
3 years ago
1. Evaluate -3x^3 -2y^2 when x=-5 and y =3
-Dominant- [34]

Answer:

357

Step-by-step explanation:

A) We replace x = - 5 and u = 3 into -3x^3 -2y^2

and we have -3x^3 -2y^2= -3*(-5)^3 -2*3^2= -3*(-125)- 2*9

or -3x^3 -2y^2 = 375-18= 357

The answer is 357.

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Have a good day.

8 0
3 years ago
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