Given sinθ = 2/5 and cosθ < 0:
1. Find cscθ
2. Find cotθ
1 answer:
Recall that
sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1
for all <em>θ</em>, and given that cos(<em>θ</em>) < 0, we find that
cos(<em>θ</em>) = -√(1 - sin²(<em>θ</em>)) = -√(1 - (2/5)²) = -√(21)/5
Now,
csc(<em>θ</em>) = 1/sin(<em>θ</em>) = 1/(2/5) = 5/2
and
cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>) = (-√(21)/5)/(2/5) = -√(21)/2
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