Given that question: Shyam invested money in the stock market. In the first
year, his stock increased 20%. He paid his stock broker $300 and then lost
$450. He withdrew $500, and then his remaining investment doubled. Shyam’s investment is now worth $7100. How much was Shyam’s original investment?
The solution is as follows:
Let the amount Shyam invested in the stock market be x, then in the first year his stock increased by 20% giving 1.2x.
He paid his stockbrocker $300 to have 1.2x - $300 left, and he lost $450 to have 1.2x - $300 - $450 = 1.2x - $750 left.
He withdrew $500 to have 1.2x - $750 - $500 = 1.2x - $1,250 left.
His remaining investment doubled to have 2(1.2x - $1,250) = 2.4x - $2,500
Shyam's investment is now worth $7,100 which means that
2.4x - $2,500 = $7,100
2.4x = $7,100 + $2,500 = $9,600
x = $9,600 / 2.4 = $4,000
Therefore, the value of Shyam's original investment is $4,000
Answer:
B.(-12,9) thats the answer enjoy :>
(n^4 - 1) = (n^2 - 1) (n^2 +1) = (n - 1) (n + 1) (n^2 + 1)
The difference between the two polynomials is 11x²3y³ - 4xy².
<h3>What is the Difference between the Polynomials?</h3>
The difference between two polynomials is the result you get by subtracting one from the other.
Thus:
= (4x²2y³ + 2xy² – 2y) – (–7x²y³ + 6xy² – 2y)
= 4x²2y³ + 2xy² – 2y + 7x²y³ - 6xy² + 2y
= 11x²3y³ - 4xy²
Learn more about polynomials on:
brainly.com/question/2833285
#SPJ1
Answer:
1.
E(down) / Odd(Across) H T
H (1,-1) (-1,1)
T (-1,1) (1,-1)
2. Even doesn't have a dominant strategy as both the strategies are providing equal payoffs for pure strategy.
