Answer:
35/68
Step-by-step explanation:
The first box contains 3 orange balls and 4 black balls.
The second box contains 5 orange balls and 6 black balls
Total number of boxes = 2
Let Pr(F) be the probability that the first box is picked.
Let Pr(S) be the probability that the second ball is picked
Let O be the orange ball selected
Pr(F) = 1/2
Pr(S) = 1/2
Pr(O|S) = n(O) / n(S)
= 5/ 6+5
5/11
Pr(O|F) = n(O) / n(F)
= 3/ 4+3
= 3/7
Pr(S|O) = [Pr( O|S).P(S)] / [Pr( O|S).P(S) + Pr( O|F).P(F)]
= (5/11*1/2) / (5/11*1/2) +(3/7*1/2(
= (5/22) / (5/22 + 3/14)
= (5/22) / (136/308)
= 35/68
Answer:
After the extended period of time, Pete would have typed 6400 words.
Step-by-step explanation:
Given the data in the question;
In the same time;
number typed word of Pete = 80
type word of Ralph = 50
After a period time;
number of typed word of Pete = ?
number of typed word of Ralph = 4000
so, let x represent the number of typed word by Pete after an extended period.
so
80 words = 50 words
x words = 4000 words
we cross multiply
x × 50 = 4000 × 80
x = ( 4000 × 80 ) / 50
x = 320000 / 80
x = 6400
Therefore, After the extended period of time, Pete would have typed 6400 words.
R - Right Handed
L - Left Handed
R = 9L ( the number of right handed kids is equal to having 9*number of left handed kids)
9L + L = 30 ( since total number of people in class is 30)
10L = 30
( Divide by 10 both sides )
L = 3
so... There are 3 Left Handed kids and 27 Right Handed kids ( since R = 9L , R = 9(3) = 27)
Hope this helped!
Answer:
My own answer to your question is x=10
Answer:
D) L = 315 cm2 ; S = 399.9 cm2
Step-by-step explanation:
Lateral area;
3 × (½)(14)(15)
315 cm²
Surface area:
315 + (½)(14)(14)sin(60)
399.8704896 cm²
