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Leokris [45]
3 years ago
8

Evaluate sec 3pi/2 to the nearest hundredth. The angle is given in radians. 0 1 undefined –1

Mathematics
2 answers:
aev [14]3 years ago
5 0

Answer:

undefined

Step-by-step explanation:

We know that value of cos\dfrac{3\pi}{2}=0

Also, secx=1/cosx

Hence, sec\dfrac{3\pi}{2}=\dfrac{1}{cos\dfrac{3\pi}{2}}

This implies sec\dfrac{3\pi}{2}=\dfrac{1}{0}

i.e.  sec3π/2 is undefined

Sever21 [200]3 years ago
4 0
\cos\dfrac{3\pi}2=0\implies \sec\dfrac{3\pi}2=\dfrac10

but this quantity is undefined.
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In a survey 27% of the people chose salads over a meat dish and in all 81 people chose salads. How many people were in the surve
Kobotan [32]
27%=27/100


so 27/100=81/x


27x=8100  divide by 27
x=300

that the answer

6 0
3 years ago
Evaluate the line integral using the fundamental theorem of line integrals. use a computer algebra system to verify your results
mario62 [17]
\dfrac{\partial f}{\partial x}=\cos x\sin y\implies f(x,y)=\sin x\sin y+g(y)

\dfrac{\partial f}{\partial y}=\sin x\cos y=\sin x\cos y+\dfrac{\mathrm dg}{\mathrm dy}
\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C

f(x,y)=\sin x\sin y+C

\displaystyle\int_{\mathcal C}\cos x\sin y\,\mathrm dx+\sin x\cos y\,\mathrm dy=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(\frac{3\pi}2,\frac\pi2\right)-f(0,-\pi)=-1
7 0
3 years ago
Find the mean of the following: 158, 213, 107, 213, and 213. If needed, round your answer to the nearest tenth
Shalnov [3]

Answer:

180.8

Step-by-step explanation:

1. Add all the numbers

2. Divide the sum by 5

3. you get the answer

4 0
3 years ago
Read 2 more answers
What is the form of the Pythagorean triple generator?​
stepladder [879]

Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

Step-by-step explanation:

We can rewrite left side into right side form

(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

we can expand it

(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4

(x^2+y^2)^2=x^4+y^4+2x^2y^2

we can add and subtract 2x^2y^2

(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

4 0
3 years ago
Read 2 more answers
4
Paraphin [41]

Answer:

24

Step-by-step explanation:

Hope this helps have a good day

3 0
3 years ago
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