4 years ago

What is three tenths of six thousand

Mathematics

1 answer:

natka813 [3]4 years ago

8 0

Answer:

1,800

Step-by-step explanation:

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Answer: the answer is A

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A bucket contains one green block, one red block, and two yellow blocks. You choose one block from the bucket.

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b. 1
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3 years ago

X ² + x -24=0<br> factor that exact problem to answer a factoring solving problem

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Answer:

Step-by-step explanation:

x²+x-24=0

x²+x+1/4-1/4=24

x^2+x+1/4=1/4+24

$(x+\frac{1}{2})^2=\frac{1}{4}+24=\frac{1+96}{4}=(\frac{\sqrt{97} }{2})^2\\x+\frac{1}{2} =\pm \frac{\sqrt{97} }{2} \\either ~x+\frac{1}{2}=\frac{\sqrt{97} }{2} \\so~x+\frac{1-\sqrt{97}}{2}=0\\ or~x+\frac{1}{2} =-\frac{\sqrt{97} }{2} \\or~x+\frac{1+\sqrt{97}}{2}=0\\ Hence~ x^2-x-24=(x+\frac{1+\sqrt{97} }{2})(x+\frac{1-\sqrt{97} }{2})$

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3 years ago

When you divide the number of permutations of 11 objects taken 3 at a time by 3!, you will get the number of combinations of 11

Sloan [31]

Answer:

Yes

Step-by-step explanation:

Permutation :

nPr = n! ÷ (n - r)!

nCr = n! ÷ (n-r)!r!

11 objects taken 3 at a time :

11P3 = 11! ÷ (11 - 3)!

11P3 = 11! / 8!

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Dividing by 3!

3! = 3*2*1 = 6

= 990 / 6

= 165

For combination :

11C3 = 11! ÷ 8!3!

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11C3 = 990 / 6

11C3

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3 years ago