6!+7!+8!=(n)(6!)
calculate the individual values first:
6!=720
7!=5040
8!=40320
plug them into the equation:
720+5040+40320=n720
solve for n
5760+40320=n720
46080=n720
divide both sides by 720 to isolate n
46080/720=n720/720
64=n
Answer:
630/x+5 (remainder over divisor)
30,240
60x24=1440x7=10,080x3= 30,240
Answer:
B
Step-by-step explanation:
Also the answer must be under 9 so that rules out option D
Because We know CE = 2 and AD is visibly larger than CE, 6We can rule out option A
And that brings us down to B and C
CB is equal to 6, And I'm no genius, but I'm pretty sure AD is DEFINATLY not equal to 6.
so the answer is B
So 25%=1/4 so technically you just do 5 times 4 since you need 4 more to have a full 4/4 or full 100% so 5 times 4 is 20 so there are 20 totals toys in the bag