Answer:
(a)ΔLAW≅ ΔWKL
(b) ASA rule of Congruency
Step-by-step explanation:
It is given that AW⊥WL and WL⊥KL, also ∠AWL=∠KLW ( Each 90°) and ∠ALW=∠LWK( Alternate angles) from the figure.
From ΔLAW and ΔWKL, we have
∠AWL=∠KLW ( Each 90°)
WL=WL (Common)
∠ALW=∠LWK( Alternate angles)
Therefore, by ASA rule of congruency,
ΔLAW≅ ΔWKL.
Hence proved.
