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Natasha_Volkova [10]
3 years ago
7

I WILL AWARD BRAINLIEST!! PLEASE PLEASE HELP!!

Mathematics
2 answers:
ANEK [815]3 years ago
5 0

Answer:

(a)ΔLAW≅ ΔWKL

(b) ASA rule of Congruency

Step-by-step explanation:

It is given that AW⊥WL and WL⊥KL, also ∠AWL=∠KLW ( Each 90°) and ∠ALW=∠LWK( Alternate angles) from the figure.

From ΔLAW and ΔWKL, we have

∠AWL=∠KLW ( Each 90°)

WL=WL (Common)

∠ALW=∠LWK( Alternate angles)

Therefore, by ASA rule of congruency,

ΔLAW≅ ΔWKL.

Hence proved.

kow [346]3 years ago
3 0

Answer:

(a)ΔLAW≅ ΔWKL

(b) ASA rule of Congruency

Step-by-step explanation:

It is given that AW⊥WL and WL⊥KL, also ∠AWL=∠KLW ( Each 90°) and ∠ALW=∠LWK( Alternate angles) from the figure.

From ΔLAW and ΔWKL, we have

∠AWL=∠KLW ( Each 90°)

WL=WL (Common)

∠ALW=∠LWK( Alternate angles)

Therefore, by ASA rule of congruency,

ΔLAW≅ ΔWKL.

I hope I helped you!! <3

- caramel

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